How to XOR two cells from the same cell array?

Hello,

I have one array of size 1x1024. I want to XOR each cell of the array. The first cell remains the same.It is as follows

Let T represent the position of each cell, then

      CellT` = {Cell T XOR Cell(T-1) for T=2..1024

                Cell T               for T=1

Lets consider a 1x10 array.It is of the following form.

 X= ['0000000000000001'  '0000000000000010'  '0000000000000011'    '0000000000000100'  '0000000000000101'  '0000000000000110'  '0000000000000111'  '0000000000001000'  '0000000000001001'  '0000000000001010']

So I need to XOR the adjacent elements except the first one. Please help thanks in advance.

[Guillaume]

It sounds that your array with cells is just a plain matlab matrix, in which case you'd be better off calling the cells elements

Cell arrays, whose elements are cells are something very different in matlab.

Answer 1

[Michael Haderlein]

With "cell", do you mean you have a cell array or do you refer to the elements of a normal logical array? I suppose second, then it's just

T =

       1     1     0     0     1

>> XORT=xor(T(2:end),T(1:end-1))

XORT =

       0     1     0     1

In case it's really a cell array, you can either translate the cell array into a normal array (cell2mat) or apply cellfun here:

>> Tc=num2cell(T)

Tc = 

      [1]    [1]    [0]    [0]    [1]

>> XORTc=cellfun(@(x,y) xor(x,y),Tc(2:end),Tc(1:end-1))

XORTc =

       0     1     0     1

Hope that's answering your question!

[Abirami]

Thank you so much sir. I've edited the qn once again to specify what i have as the input.

[Michael Haderlein]

With respect to your modified question, you can do the following:

>> T= {'0000000000000001'  '0000000000000010'  '0000000000000011'    '0000000000000100'  '0000000000000101'  '0000000000000110'  '0000000000000111'  '0000000000001000'  '0000000000001001'  '0000000000001010'};
>> Tc=cellfun(@(x) x=='1',T,'uniform',false);
>> XORTc=[Tc(1) cellfun(@(x,y) xor(x,y),Tc(2:end),Tc(1:end-1),'uniform',false)];

The first use of cellfun translates the string arrays into logical arrays and the second performs the xor along with the concatenation with the first value of Tc.

Answer 2

[Guillaume]

If you are operating on strings of '0' and '1', then the xor operation is the same as the ~= operation plus a conversion back to string.

binstrxor = @(binstr1, binstr2) char('0' + (binstr1 ~= binstr2));

Thus:

X = {'0000000000000001'  '0000000000000010'  '0000000000000011'    '0000000000000100'  '0000000000000101'  '0000000000000110'  '0000000000000111'  '0000000000001000'  '0000000000001001'  '0000000000001010'};
Xxor = cellfun(binstrxor, X(1:end-1), X(2:end), 'UniformOutput', false)

Note that the strings must be the same length (same number of bits) for ~= to work.

[Michael Haderlein]

+1 - that's shorter than my solution.