Why this error using integral function?

1 回表示 (過去 30 日間)
Ove Gustafsson
Ove Gustafsson 2015 年 3 月 10 日
コメント済み: Ove Gustafsson 2015 年 3 月 11 日
What is wrong?
>> T = @(x) 1/x; >> Q=integral(T,1,1000); Undefined function 'minus' for input arguments of type 'function_handle'.
Error in integral (line 4) N=(hmax-hmin)/0.0001;

採用された回答

Michael Haderlein
Michael Haderlein 2015 年 3 月 10 日
Fun thing is I get a different error message:
Error using /
Matrix dimensions must agree.
Anyway, if you change your definition of T to
T=@(x) 1./x;
(note the dot!), it should work.
  1 件のコメント
Ove Gustafsson
Ove Gustafsson 2015 年 3 月 11 日
Thank you for the answer. You are right it has to be 1./x since the function has to handle arrays, but the main problem was quit different. Since I downloaded a set of MatLab-files within an application that used the name integral for a function of there own, integral.m, and the path was set so MatLab was looking there first. the new integral.m didn't work in the same way as the original integral.m of MatLab. Sorry for troubling you with a trivial problem. Best regard

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeMathematics についてさらに検索

タグ

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by