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Contour plot for a non rectangular object

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Ghazwan
Ghazwan 2022 年 10 月 5 日
コメント済み: William Rose 2022 年 10 月 6 日
I have this case that I worked out in another software.
In the attached file, you can see the X,Y coordinates. The third column represents the results that I need to plot in a contour silimar to the one in the image above.
I tried several codes, but all of them plot on a rectagular area and/or not showing the same shape for the contour area. For example, the following code:
xyz = xlsread('data.xlsx');
x=xyz(2:end,1);
y=xyz(2:end,2);
z=xyz(2:end,3);
[X,Y]=meshgrid(min(x):max(x),min(y):max(y));
Z=griddata(x,y,z,X,Y);
contour(X,Y,Z)

採用された回答

William Rose
William Rose 2022 年 10 月 5 日
[X,Y]=meshgrid(x,y) makes a grid where all the x values are the same across the grid, and likewise for yhe y values.
You can fix it by making your own X and Y instead of using meshgrid.
Nx=41; Ny=9;
dx=1; dy=1; %adjust as desired
x=((0:Nx-1)-(Nx-1)/2)*dx; y=((0:Ny-1)-(Ny-1)/2)*dy;
[X,Y]=meshgrid(x,y); %initial approximation
Z1=X+2*Y;
subplot(211); surf(X,Y,Z1);
xlabel('X'); ylabel('Y'); axis equal; view(0,90)
%next: adjust the grid Y-values
Yadj=Y;
for i=1:Nx
if i<=5||i>=37
ymult=1;
elseif i>=32
ymult=(i-25)/12;
elseif i<=10
ymult=(17-i)/12;
else
ymult=0.5;
end
Yadj(:,i)=ymult*Y(:,i);
end
subplot(212); surf(X,Yadj,Z1);
xlabel('X'); ylabel('Yadj'); axis equal; view(0,90)
It works. The code to adjust the y-values is not very elegant, but it demonstrates the possibilities for creating a non-retangular grid.
  4 件のコメント
Ghazwan
Ghazwan 2022 年 10 月 6 日
Thank you, William. This is excellent.
Your code gave me a good idea of what to do next. After I generate the proper coordinate array, I will interpolate the original contour data into the new array. This way, I can ensure that the contour data will get appropriately mapped into the new coordinate points.
William Rose
William Rose 2022 年 10 月 6 日
@Ghazwan, you are welcome. Your plan sounds good.

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