フィルターのクリア

Gauss-Markov process generation: how to filter a white noise sequence properly

48 ビュー (過去 30 日間)
Johnny Scalera
Johnny Scalera 2022 年 9 月 9 日
編集済み: Adil 2022 年 9 月 14 日
Hi all,
I'm trying to generate a first order Gauss-Markov process (https://en.wikipedia.org/wiki/Gauss%E2%80%93Markov_process).
From signal processing theory, it is known that this could be performed filtering a white gaussian noise properly (noise shaping filter).
This filter should have a transfer function equal to:
with the two parameters %sigma, %beta that have to be tuned and that will described completely the Gauss-Markov process.
fs = 100;
Nsamples = 2000;
rng('default');
gaussianNoise = randn(Nsample, 1);
whiteGaussianNoise = (gaussianNoise - mean(gaussianNoise)) / std(gaussianNoise);
beta = 0.01;
sigma = 0.1;
b = sqrt(2 * beta * sigma^2);
a = [1, beta];
gaussMarkov = filter(b,a,whiteGaussianNoise);
This is the code I used for the Gauss Markov synthetis. Unfortunately, something is wrong because it has a similar power spectral density and a similiar autocorrelation of the white noise. In the link provided above, the correct auocorrelation and psd are defined.
What's wrong with this code? Why I cannot generate a Gauss Markov process?
Thank you all.

回答 (1 件)

Adil
Adil 2022 年 9 月 9 日
編集済み: Adil 2022 年 9 月 13 日
I'm not sure if that's the reason for your problem, but you're using a transfer function in the s-domain G(s) and it looks like the MATLAB filter function uses a transfer function in the z-domain G(z).
So maybe it will work after applying this method: Matched Z-transform method - Wikipedia
EDIT:
Ok, now I'm sure, just watch this video: https://www.youtube.com/watch?v=88tWmyBaKIQ and you will see that you can just use the bilinear transform and get (for your sampling frequency) the following parameters:
b = [((sqrt(2 * beta * sigma^2))*1/fs)/(beta*1/fs + 2), (sqrt(2 * beta * sigma^2)*1/fs)/(beta*1/fs + 2)];
a = [1,(beta*1/fs - 2)/(beta*1/fs + 2)];
  2 件のコメント
Johnny Scalera
Johnny Scalera 2022 年 9 月 14 日
Thank you @Adil for your answer. I am taking into account your observation.
Using the bilinear transform described in the section 9.2 Converting S Domain to Z Domain of this page
I obtain this transfer function in the z domain
So my two vectors of coefficients are
k = sqrt(2*beta*sigma^2) / (beta+1)
b = [k, k]
a = [1, (beta-1) / (beta+1)]
Am I right? Why do you use different coefficients?
Adil
Adil 2022 年 9 月 14 日
編集済み: Adil 2022 年 9 月 14 日
Hi Johnny,
I'm not sure why your source uses a different bilinear transform without dependency of dt, but as you suggested in your entry post: You can check the generated signal via its autocorrelation function, psd or Allan deviation plot.
So if I'm checking the gauss markov signal which was created with your parameters, then I can unfortunately see no exponentially time correlated autocorrelation plot, as expected.
But with the parameters which I posted above, I can see it.
[Rxx, lags] = xcorr(gaussMarkov);
figure();
plot(lags, Rxx);
This shape is what you would expect: https://www.researchgate.net/profile/Spiros_Pagiatakis/publication/232711015/figure/download/fig14/AS:668420496453664@1536375273795/Autocorrelation-function-of-the-first-order-Gauss-Markov-process.png
I calculated the coeffitients as described here: Bilinear transform - Wikipedia with s = (2 - 2z^(-1))/(dt + dtz^(-1))
I hope this helps

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeCorrelation and Convolution についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by