Central part of a matrix
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Hello,
If a have a Matrix M and I want to create a new one, call it Central_M, which should be the central part of M and of a defined size s, how can I do it?
M_central = ?
Thanks in advance for your reply.
2 件のコメント
Chris McComb
2015 年 2 月 24 日
What exactly do you mean by 'central'? And can you define s?
Auryn_
2015 年 2 月 25 日
回答 (2 件)
Jos (10584)
2015 年 2 月 25 日
Something like this?
M = spiral(10) % test matrix
S = 2 % s elements around the central position
% the resulting matrix will be 2*S+1 squared in size
dx = -S:S ;
RC0 = ceil(size(M)/2) % central position
OUT = M(RC0(1)+dx, RC0(2)+dx)
1 件のコメント
Sean de Wolski
2015 年 2 月 25 日
+1 for spiral!
RAGHAVENDRA
2015 年 2 月 25 日
編集済み: Guillaume
2015 年 2 月 25 日
M_central=M(floor(size(M,1)/2)-floor(s/2):floor(size(M,1)/2)+floor(s/2),floor(size(M,2)/2)-floor(s/2):floor(size(M,2)/2)+floor(s/2));
The above instruction will work, you can use 'round' instead of 'floor' to change the matrix indices accordingly.
3 件のコメント
Guillaume
2015 年 2 月 25 日
Please use the {} Code button to format code in your answer
Auryn_
2015 年 2 月 25 日
RAGHAVENDRA
2015 年 2 月 25 日
編集済み: RAGHAVENDRA
2015 年 2 月 25 日
It is working perfectly for me, this is the example that i have tried
M=randi(5,[10 10]);
s=2;
M_central=M(floor(size(M,1)/2)-floor(s/2):floor(size(M,1)/2)+floor(s/2),floor(size(M,2)/2)-floor(s/2):floor(size(M,2)/2)+floor(s/2))
What is the error message?
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