Legend Producing Wrong Colour Lines
古いコメントを表示
Hi I have been trying to plot multiple lines on the same plot and the colours of the lines are coming up incorrectly. Here is my code and the results. I am currently running 2020b
plot(x,freal,'k')
hold on
plot(x,ftaylor0,'r')
plot(x,ftaylor1,'b')
plot(x,ftaylor2,'g')
plot(x,ftaylor3,'m')
plot(x,ftaylor4,'c')
hold off
legend('f(x)', 'p0(x)', 'p1(x)', 'p2(x)', 'p3(x)', 'p4(x)')
xlabel('x')
ylabel('f(x)')

回答 (1 件)
x=-5:0.1:5;
freal=x.*exp(-x);
ftaylor0= 1./exp(x); % they is scalar in your code
ftaylor1= 1./exp(-x); % this is scalar in your code
ftaylor2= (1/exp(1))-(1/(2*exp(1)).*(x-1).^2);
ftaylor3= (1/exp(1))-(1./(2.*exp(1)).*(x-1).^2)+((1./(3.*exp(1))).*(x-1).^3);
ftaylor4= (1/exp(1))-(1./(2.*exp(1)).*(x-1).^2)+((1./(3.*exp(1))).*(x-1).^3)-((1./(8.*exp(1))).*(x-1).^4);
plot(x,freal,'k')
hold on
plot(x,ftaylor0,'r')
plot(x,ftaylor1,'b')
plot(x,ftaylor2,'g')
plot(x,ftaylor3,'m')
plot(x,ftaylor4,'c')
hold off
legend('f(x)', 'p0(x)', 'p1(x)', 'p2(x)', 'p3(x)', 'p4(x)')
You can see ftaylor0 and ftaylor1 are scalars with just one point. You need to make them vectors
1 件のコメント
x=-5:0.1:5;
freal=x.*exp(-x);
ftaylor0= 1./exp(1) % they is scalar in your code
ftaylor1= 1./exp(1) % this is scalar in your code
ftaylor2= (1/exp(1))-(1/(2*exp(1)).*(x-1).^2);
ftaylor3= (1/exp(1))-(1./(2.*exp(1)).*(x-1).^2)+((1./(3.*exp(1))).*(x-1).^3);
ftaylor4= (1/exp(1))-(1./(2.*exp(1)).*(x-1).^2)+((1./(3.*exp(1))).*(x-1).^3)-((1./(8.*exp(1))).*(x-1).^4);
plot(x,freal,'k')
hold on
plot(ftaylor0,'>r','MarkerSize',10) % use a marker to plot
plot(ftaylor1,'sb','MarkerSize',4) % use a marker to plot
plot(x,ftaylor2,'g')
plot(x,ftaylor3,'m')
plot(x,ftaylor4,'c')
hold off
legend('f(x)', 'p0(x)', 'p1(x)', 'p2(x)', 'p3(x)', 'p4(x)','location','best')
You can also plot them as data point with proper legend
カテゴリ
ヘルプ センター および File Exchange で Legend についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!

