How to replace first and last element of each matrix in 7x1 cell with 0

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Tomaszzz
Tomaszzz 2022 年 7 月 18 日
コメント済み: Tomaszzz 2022 年 7 月 18 日
Hi all,
I have a 7x 1 cell of 101x1 double.
I want to replace first and last element of each matrix with 0. Can you help please?
My approach:
for i = 1:length(cell)
cell{i}((cell(1:1)))=0;
cell{i}((cell(101:101)))=0;
end
Unable to use a value of type cell as an index.

採用された回答

KSSV
KSSV 2022 年 7 月 18 日
編集済み: KSSV 2022 年 7 月 18 日
for i = 1:length(cell)
cell{i}(1)=0;
cell{i}(end)=0;
end

その他の回答 (1 件)

Walter Roberson
Walter Roberson 2022 年 7 月 18 日
NewCell = cellfun(@(C) [0; C(2:end-1); 0], OldCell, 'uniform', 0);
Note: using cell as the name of a variable interfers with calling cell() to create a cell array... and confuses people reading your code.

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