casting without rounding using coder

How can I manually trigger casting from a float/double to integer without involving any rounding while using coder?

LUT = single(rand(1,2000)*200);
for i=1:2000
    ind = int32(LUT(i));
    fprintf("%i\n",ind);
end

When the C++ code is generated it will be similar to:

int ind = static_cast<int>(rt_roundf_snf(LUT[i]));

I am aware that under certain circumstances coder is able to automatically figure out the optimal datatypes for indexing inside for loops resulting then in the desired result:

int ind = static_cast<int>(LUT[i]);

Answer 1

[Bjorn Gustavsson]

Well, the only interpretation I can thing of that matches the "casting without rounding" in a sensible way is:

    ind = int32(floor(LUT2(i));

That way ind will be the integer part of whatever LUT2 is. But this is still "rounding-off the fractional part".

HTH

[Marc Barnada]

Unfortunately my interest is to simply trigger a plain static_cast<int> call without flooring, ceiling or rounding.

[Bjorn Gustavsson]

What is the crucial difference?

[Marc Barnada]

I want to have highly efficient C++ code, and that extra call to rt_roundf_snf has a big impact in the timings of a Look-Up-Table (LUT) function.

[Bjorn Gustavsson]

If it is a limited point-of-use and a one-time effort would it be possible to manually edit the generated code?