フィルターのクリア

Create a matrix that changes size according to a variable N

11 ビュー (過去 30 日間)
wissal zaher
wissal zaher 2022 年 7 月 10 日
コメント済み: Steven Lord 2022 年 7 月 11 日
Hello,
I'm working on a project consisting of creating an MPC controller from scratch and the matrices need to be defined in a way where the size can change given a variable N (the prediction Horizon). I've already wirtten the matrices for N=7 but how can I do so for a flexible N input.
The size of the Matrices is given below.
A,B,Q,R, x_min, x_max, u_min, u_max are defined as follow :
A = [1 0.1;0 1]
B = [0.005;0.1]
Q = [1 0;0 1]
R = 0.1
x_min = [-5;-5]
x_max = [5;5]
u_min = -1
u_max = 1

採用された回答

patrick1704
patrick1704 2022 年 7 月 10 日
Well, one option on how to e.g. create your is to do something like this:
Atilde = arrayfun(@(x) A.^x, 0:1:n, 'UniformOutput',false).';
Atilde = vertcat(Atilde{:});
Naturally, doing everything in a for-loop using if-clauses is also an option. It mainly depends on how efficient you need the implementation to be.
  2 件のコメント
wissal zaher
wissal zaher 2022 年 7 月 11 日
編集済み: wissal zaher 2022 年 7 月 11 日
For Atilde it worked nicely :)
Bor Btilde I think I have to create a loop .. any ideas ?
And thank you for the reply
Steven Lord
Steven Lord 2022 年 7 月 11 日
Bor Btilde I think I have to create a loop .. any ideas ?
Create a for loop?
You may have heard that "for loops in MATLAB are slow." At one time, years ago, that may have been true. It has become less and less true as we've enhanced the language.
If for loops are the right tool for the job, use them.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeController Creation についてさらに検索

製品


リリース

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by