- 'Format' governs what the output looks like
- 'InputFormat' governs what the input looks like
Datetime won't recognise some cells
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I have a series of datetimes in the format 'HH:mm:ss.sss'. I am using the following code to convert from string into datetimes.
data.TimeofDay = datetime(data.TimeofDay,'Format','HH:mm:ss.sss')
In the attached .mat file, it contains the data file before and after the command above. For some reason, different values in the column are returned as NaT despite all rows seemingly being in the same format.
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the cyclist
2022 年 6 月 28 日
編集済み: the cyclist
2022 年 7 月 9 日
Relevant for both your code and some of the answers:
In your case, I believe MATLAB would have correctly inferred your input format, if had you left it unspecified:
datetime(data.TimeofDay)
採用された回答
Cris LaPierre
2022 年 6 月 28 日
For miliseconds, you want to use a capital 'S'.
load datetime-problem.mat
datetime(databackup.TimeofDay,'Format','HH:mm:ss.sss')
% corrected
datetime(databackup.TimeofDay,'Format','HH:mm:ss.SSS')
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その他の回答 (2 件)
the cyclist
2022 年 6 月 28 日
編集済み: the cyclist
2022 年 6 月 28 日
Two minor but important changes to your syntax:
datetime(data.TimeofDay,'InputFormat','HH:mm:ss.SSS')
Note that I used
- 'InputFormat' instead of 'Format'
- .SSS instead of .sss
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Voss
2022 年 6 月 28 日
load datetime-problem.mat
databackup.TimeofDay
% original Format specification:
datetime(databackup.TimeofDay,'Format','HH:mm:ss.sss')
% corrected Format specification:
datetime(databackup.TimeofDay,'Format','hh:mm:ss.SSS')
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