I have a problem while ploting this code.

Fs = 4000;

Channels = 1;

bits = 16;

duration = 5;

t = 0:1/Fs:(length(x)-1)/Fs;

r = audiorecorder(Fs, bits, Channels);

disp('Recording Start')

recordblocking(r, duration);

disp('Recording Stop')

X = getaudiodata(r);

sound(X, Fs, bits);

filename = 'myvoice.wav';

audiowrite(filename, X, Fs);

n = length(X); F = 0:(n-1)*Fs/n;

Y = fft(X,n);

F_0 = (-n/2:n/2-1).*(Fs/n);

Y_0 = fftshift(Y);

AY_0 = abs(Y_0);

figure(1)

plot(t, X, 'LineWidth',1.5);

xlabel('time (sec)'); ylabel('Amplitude');

title('Time Domain Plot of the Recorded Signal');

figure(2)

plot(F_0), AY_0, 'LineWidth',1.5);

xlabel('Frequency (Hz)'); ylabel('Amplitude');

title('Frequency Domain Plot of the Recorded Signal');

Recording Start

Recording Stop

Error using plot

Vectors must be the same length.

Answer 1

[VINAYAK LUHA]

Hi Essa ,

I couldn't reproduce the mentioned error as you haven't specified the value of 'x' hence code breaks before the plot function executes. Hope the follwing code solves your problem.

little explanation:

Since X will have 20,000 values (Fs*duration) ,I just stored the timestamps of each samples in t and plotten X vs t.

Fs = 4000;

Channels = 1;

bits = 16;

duration = 5;

t = (0:1/Fs:duration-1/Fs)';

r = audiorecorder(Fs, bits, Channels);

disp('Recording Start')

recordblocking(r, duration);

disp('Recording Stop')

X = getaudiodata(r);

sound(X, Fs, bits);

filename = 'myvoice.wav';

audiowrite(filename, X, Fs);

n = length(X); F = 0:(n-1)*Fs/n;

Y = fft(X,n);

F_0 = (-n/2:n/2-1).*(Fs/n);

Y_0 = fftshift(Y);

AY_0 = abs(Y_0);

figure(1)

plot(t,X, 'LineWidth',1.5);

xlabel('time (sec)'); ylabel('Amplitude');

title('Time Domain Plot of the Recorded Signal');

figure(2)

plot((F_0), AY_0, 'LineWidth',1.5);

xlabel('Frequency (Hz)'); ylabel('Amplitude');

title('Frequency Domain Plot of the Recorded Signal');