how can i make my scattered 3 dimensional data points as a 3d surface?

I am having the matrix k where each row represents a 3dimensional point.Each column of the matrix represents the respective dimensional value of each point.How can i make the 3d surface for the matrix?Kindly need help as soon as possible. >> k
k =
1.0e+03 *
0.0124 8.6000 0.0308
0.0099 9.8400 0.0355
0.0108 8.3200 0.0347
0.0118 8.0800 0.0490
0.0127 8.5800 0.0327
0.0133 7.8600 0.0438
0.0141 8.1600 0.0322
0.0102 8.1800 0.0490
0.0101 8.6800 0.0322
0.0134 8.1000 0.0372
0.0134 8.3000 0.0338
0.0130 7.3600 0.0550
0.0137 7.1200 0.0323
0.0096 9.1200 0.0372
0.0179 7.4800 0.0283
0.0100 8.4900 0.0372
Thanks in advance.

回答 (1 件)

Alessandro Masullo
Alessandro Masullo 2015 年 1 月 27 日

0 投票

tri = delaunay(k(:,1),k(:,2));
trisurf(tri,k(:,1),k(:,2),k(:,3))

2 件のコメント

Ranjini Anbu
Ranjini Anbu 2015 年 1 月 30 日
Thanks for your answer.But i need to draw surface like this.
The surface in your image is provided on a regular grid, while your data are not. You need to interpolate your data on a structured grid (created with meshgrid) using scatteredInterpolant.
k = 1.0e+03 *[ 0.0124 8.6000 0.0308
0.0099 9.8400 0.0355
0.0108 8.3200 0.0347
0.0118 8.0800 0.0490
0.0127 8.5800 0.0327
0.0133 7.8600 0.0438
0.0141 8.1600 0.0322
0.0102 8.1800 0.0490
0.0101 8.6800 0.0322
0.0134 8.1000 0.0372
0.0134 8.3000 0.0338
0.0130 7.3600 0.0550
0.0137 7.1200 0.0323
0.0096 9.1200 0.0372
0.0179 7.4800 0.0283
0.0100 8.4900 0.0372];
f = scatteredInterpolant(k(:,1),k(:,2),k(:,3),'natural','linear');
[x,y] = meshgrid(linspace(min(k(:,1)),max(k(:,1)),50),linspace(min(k(:,2)),max(k(:,2)),50));
z = f(x,y);
figure
surf(x,y,z)

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2015 年 1 月 27 日

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2021 年 8 月 20 日

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