find the delay between two signals

34 ビュー (過去 30 日間)
Yunyu Hu
Yunyu Hu 2022 年 5 月 13 日
コメント済み: Yunyu Hu 2022 年 5 月 16 日
I have two signals like following:
They are the same length (200),
But d = finddelay(x,y) shows
d=0;
It cannot find the correct delay between them. Which function can be used here to get the right solution?

採用された回答

Jonas
Jonas 2022 年 5 月 13 日
use xcorr(sig1,sig2), and use the max value of xcorr. the corresponding delay can be found at the corresponding value in the lag output (second output)
  3 件のコメント
Jonas
Jonas 2022 年 5 月 16 日
編集済み: Jonas 2022 年 5 月 16 日
you are using the output not correctly. lag contains the corresponding lag value of the correlation calues of the first input. you need to find the lag value of the maximum correlation
dt=0.8;
x=[10,11,12,13,14,15,16,15,14,12];
t1=0:dt:(numel(x)-1)*dt;
y=[10,10,10,10,11,12,13,14,15,16,15,14,12];
t2=0:dt:(numel(y)-1)*dt;
figure;
original=subplot(3,1,1);
plot(t1,x); hold on; plot(t2,y);
title('original')
xlabel('time');
[corrVal,lag]=xcorr(x,y);
lagplot=subplot(3,1,2);
plot(lag*dt,corrVal,'-+');
xlabel('lag');
ylabel('xcorr value');
[~,maxCorrIdx]=max(corrVal);
lagAtMaxVal=lag(maxCorrIdx);
aligned=subplot(3,1,3);
plot(t1,x,'-*'); hold on; plot(t2+lagAtMaxVal*dt,y,'-s');
title('aligned');
xlabel('time')
linkaxes([original lagplot aligned],'x');
Yunyu Hu
Yunyu Hu 2022 年 5 月 16 日
Hi, Thanks a lot for the explaination! It is quite reasonable.
And I found the reason, why both xcorr and finddelay cannot give me the correct answer for my original signals. Because the peak is downwards.
If I change the the x and y like this:
x=20-[10,11,12,13,14,15,16,15,14,12];
y=20-[10,10,10,10,11,12,13,14,15,16,15,14,12];
and run your codes, it can also not find the correct answer.
I think this is the limitation of cross correlation. But I can do conversion on signals. :-)

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeCorrelation and Convolution についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by