フィルターのクリア

Can vpasolve restrict the numerical solution to be a real number? If it can, how should I stipulate this condition?

34 ビュー (過去 30 日間)
I have eight unknown variables and eight equations. Now I use the vpasolve to find the numerical solution of the equation, hoping to get only the real solution, but the vpasolve only returns a complex solution. Can I restrict the it to output only real solutions? If I can, how should I implement it? Thank you for your reply.

回答 (2 件)

Dyuman Joshi
Dyuman Joshi 2022 年 4 月 24 日
syms x
S = vpasolve(x^6 - x^2 == 3, x)
S = 
assume(x,'real')
S = vpasolve(x^6 - x^2 == 3, [-Inf Inf])
S = 

jessie sun
jessie sun 2022 年 4 月 25 日
Dear @Dyuman Joshi, I used "assume" to restrict the unknown variables to be real numbers:
But the output result was not as I expected:
  3 件のコメント
Walter Roberson
Walter Roberson 2022 年 4 月 25 日
Tips:
vpasolve ignores assumptions set on variables. You can restrict the returned results to particular ranges by specifying appropriate search ranges using the argument init_param.
jessie sun
jessie sun 2022 年 4 月 25 日
Thank you for your answer. By using your method, the problem has been solved.@Dyuman Joshi@Walter Roberson

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLoops and Conditional Statements についてさらに検索

製品


リリース

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by