Generating empty interval of points

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imola
imola 2015 年 1 月 14 日
コメント済み: Star Strider 2015 年 1 月 15 日
Dear All,
I want to generate points in the interval [20,80] and have the interval [40,60] as an empty area. I wrote this code but I don't now how to complete it. I'd appreciate any help.
LB=20;UB=80;
x = LB+(UB-LB)*rand(50,1);
y =LB+(UB-LB)*rand(50,1);
if x>40 | x<60| y>40 | y<60;
[x]==0;[y]==0;
plot(x,y, '.')
but it gives an error.
Regards

採用された回答

Star Strider
Star Strider 2015 年 1 月 14 日
This seems to work:
LB=20;UB=80;
x = LB+(UB-LB)*rand(50,1);
y = LB+(UB-LB)*rand(50,1);
idx = [((x > 40) & (x < 60)) | ((y > 40) & (y < 60))];
x(idx) = [];
y(idx) = [];
figure(1)
plot(x, y, '+')
grid
The ‘idx’ variable tests for the conditions and creates a logical vector then used to assign the elements of ‘x’ and ‘y’ to ‘empty’ rather than zero. The plot shows that there are no points in the area you want cleared.
  5 件のコメント
imola
imola 2015 年 1 月 15 日
Thanks Star, that's fine, it works perfectly .
Regards
Star Strider
Star Strider 2015 年 1 月 15 日
My pleasure!

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その他の回答 (1 件)

Roger Stafford
Roger Stafford 2015 年 1 月 14 日
Do this:
LB=20;UB=80;
x = LB+(UB-LB)*rand(50,1);
y = LB+(UB-LB)*rand(50,1);
t = ((x<=40)|(x>=60)) & ((y<=40)|(y>=60));
x = x(t);
y = y(t);
plot(x,y,'.')
  1 件のコメント
imola
imola 2015 年 1 月 14 日
Dear Roger, Thanks for you and for star for answer me, I realize that I didn't explain what I want exactly, forgave me both of you, with your code I got four areas of points separate of each other while I need a whole area of points and an empty area in the middle, is like an empty square inside a big square of points, so I tried to use
t = ((x<=40)||(x>=60)) && ((y<=40)||(y>=60));
but its wrong, could you please sorted to me.
Regards,
Imola.

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