How to split columns up into different numbers of figures?

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Mary292
Mary292 2015 年 1 月 13 日
コメント済み: Image Analyst 2015 年 3 月 7 日
If I have a matrix of data, X, which has 30 columns. Is there some way of using an if statement or something similar to divide the columns up to produce 5 figures. E.g. the first figure would contain columns 1-3 and the the second figure would contain columns 4-6 etc.
  2 件のコメント
Nicholas
Nicholas 2015 年 1 月 13 日
Hi marie - you could use a 'if' inside a 'for' loop for this.
Image Analyst
Image Analyst 2015 年 3 月 7 日
Original question in case Mary overwrites if with gibberish like her other questions:
If I have a matrix of data, X, which has 30 columns. Is there some way of using an if statement or something similar to divide the columns up to produce 5 figures. E.g. the first figure would contain columns 1-3 and the the second figure would contain columns 4-6 etc.

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採用された回答

Sara
Sara 2015 年 1 月 13 日
% This values are here just to show an example
n = 7; % num
A = zeros(10,n);
for i = 1:n
A(:,i) = i;
end
ncols = 3; % columns per plot
niter = ceil(n/ncols);
for i = 1:niter
figure
kstart = (i-1) * ncols + 1;
kend = min(kstart + ncols-1 ,n);
for j = kstart:kend
plot(A(:,j)),hold on
end
ylim([0 10])
end

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