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syms variable also a variable of loop

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Dharma Khatiwada
Dharma Khatiwada 2022 年 4 月 11 日
回答済み: Dharma Khatiwada 2022 年 4 月 12 日
Hi all,
I am using t as syms variable and also as the variable inside loop.I am not sure whether they are connected in the code below. They need to represent the same. Is there a way I can get rid of syms and keep integration part (y2) also inside the loop? Your suggestion will be highly appreciated.
Thanks
Dharma
.....................................................................................................................................
a=0.0799;
b=5.85;
N=2000;
dt=0.05;
%
syms x t
c2(x) = (dirac(x-1) + dirac(x-3)+dirac(x-5)+dirac(x-7)+dirac(x-9)+dirac(x-11))*4;
inner2 = c2(x)* exp(-10*(t-x));
y2 = matlabFunction(simplify(int(inner2, x, 0, t)));
%
t=zeros(N,1);
K=zeros(N,1);
t(1)=0;
K(1)=20;
for i=1:N
for j=1:N
t(i+1)=t(i)+dt;
K(i+1)=K(i)-a*dt*K(i)-b*dt*t(i)*y2(t(i))*K(i);
end
end
  5 件のコメント
Dharma Khatiwada
Dharma Khatiwada 2022 年 4 月 12 日
Could you please give the detail of such steps?
Thanks
KSSV
KSSV 2022 年 4 月 12 日
Already you are doing it right?
y2(t(i))

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回答 (1 件)

Dharma Khatiwada
Dharma Khatiwada 2022 年 4 月 12 日
It is working right but it takes longer time to run. I am trying to see if the integration can also be kept inside to see relatively shorter runtime.
Please let me know.

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