Get label name of item in dropdown menu
22 ビュー (過去 30 日間)
古いコメントを表示
I have 2 dropdown menus that allow the user to select which variables to plot on a figure. I would like to also update the labels of the plot according to the label name of the selected item. Is there a way to access the label name without passing an object to ItemsData (e.g. {["var1",1],["var2",2], ...})?
data = ones(1,length(table_cols)-1); % Dummy data
eng_perf = uitab(PlotTabGroup,'Title','Engine Perf.');
perf_plot = uiaxes(eng_perf,"Units","normalized","Position",[0 0.05 1 0.95]);
% table_cols contains the names of the items
xdrop = uidropdown(eng_perf,"Position",[10 5 100 20],'Items',table_cols(2:end),...
"Tag",'xdrop',"Value",table_cols(2),"ItemsData",data);
ydrop = uidropdown(eng_perf,"Position",[120 5 100 20],'Items',table_cols(2:end),...
"Tag",'ydrop',"Value",table_cols(3),"ItemsData",data);
xdrop.ValueChangedFcn = @(xdrop,event) update_perf_plot(xdrop,ydrop,perf_plot);
ydrop.ValueChangedFcn = @(ydrop,event) update_perf_plot(xdrop,ydrop,perf_plot);
function update_perf_plot(xdrop,ydrop,perf_plot)
perf_plot.XLabel.String = xdropSelectedName; % Replace this line
perf_plot.YLabel.String = xdropSelectedName; % Replace this line
plot(perf_plot,xdrop.Value,ydrop.Value)
end
0 件のコメント
回答 (1 件)
Geoff Hayes
2022 年 4 月 12 日
@John F - since you are passing the drop down objects into the callback, I think you could just do
function update_perf_plot(xdrop,ydrop,perf_plot)
perf_plot.XLabel.String = xdrop.Value;
perf_plot.YLabel.String = ydrop.Value;
% !! Not sure what the next line is supposed to do !!
% plot(perf_plot,xdrop.Value,ydrop.Value)
end
That would allow you to set the current selection from each drop down to the appropriate label. As mentioned in the above code, it isn't clear to me how these same two values (strings) are supposed to be used in your call to plot.
There may also be alternatives to passing the drop down objects into this callback. If you have nested your callback within the main code that creates the drop downs, then you can access them directly. For example,
function nestedFunctionExample
eng_perf = uifigure;
xdrop = uidropdown(eng_perf,"Position",[10 5 100 20],'Items',{'abc' 'def' 'ghi'},...
"Tag",'xdrop',"Value",'def');
ydrop = uidropdown(eng_perf,"Position",[120 5 100 20],'Items',{'abcd' 'defd' 'ghid'},...
"Tag",'ydrop',"Value",'defd');
xdrop.ValueChangedFcn = @(xdrop,event) update_perf_plot;
ydrop.ValueChangedFcn = @(ydrop,event) update_perf_plot;
function update_perf_plot()
fprintf('xdrop=%s\n', xdrop.Value);
fprintf('ydrop=%s\n', ydrop.Value);
end
end
5 件のコメント
Geoff Hayes
2022 年 4 月 12 日
@John F - perhaps since you are mapping strings to numbers, then maybe you should try using a map object. For example,
>> myMap = containers.Map(["a","b","cd"],[1,2,3]);
>> myMap("cd")
ans =
3
You could then create two map objects, one for the x drop down and one for the y drop down. You would then do something like
perf_plot.XLabel.String = xdrop.Value;
perf_plot.YLabel.String = ydrop.Value;
plot(perf_plot,xDropMap(xdrop.Value),yDropMap(ydrop.Value))
where xDropMap and yDropMap are the containers that map the drop down elements to the appropriate value.
参考
カテゴリ
Help Center および File Exchange で Develop uifigure-Based Apps についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!