Regular polygon drawing with number of sides and number of points per side as input

6 ビュー (過去 30 日間)
Hello, I want to generate the points that define a regular polygon (a hexagon in my case). I am able to generate the vertices as:
nsides = 6; % hexagon
stepsize = 360/nsides;
theta = 0:stepsize:359;
x = cosd(theta);
y = sind(theta);
This only generates the vertices (ie 1 point per side), but I also want to include the possibility to choose the number of points per side. For the hexagon case the code above generates 6 points, but I would like the hexagon to have also 6 additional points located at the centre of each side, so 12 in total. How could I improve the code above to do this? Thanks

採用された回答

William Rose
William Rose 2022 年 3 月 30 日
There are different way you could go. One way is to define a time vector
t=0:6;
Define the corner coordinates points.
theta = 0:60:360;
x = cosd(theta);
y = sind(theta);
The initial point appear at the start and at the end. Choose the number of points per side:
M=10;
Create a time vector for interpolating the points:
t1=0:1/M:6;
Interpolate:
x1=interp1(t,x,t1);
y1=interp1(t,y,t1);
Plot x1 versus y1.
plot(x1,y1,'-k.');
axis equal
Done.
  2 件のコメント
Albert
Albert 2022 年 3 月 30 日
Excellent!! Works perfectly! Thanks
William Rose
William Rose 2022 年 3 月 30 日
@Albert, you're welcome.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeElementary Polygons についてさらに検索

製品


リリース

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by