Histogram function plots different colours from those requested
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I"m trying to color-code each of 4 histograms using a predefined color scheme. Here's a minimal working example:
colours = [0 32 96;
192 0 0;
71 207 255;
255 143 143;
] / 255;
for i=1:4
x = randn(1,100);
subplot(1,4, i)
values = histogram(x, 'FaceColor', colours (i, :));
end
However, in the image I'm getting, the colors are actually (slightly) different, for instance for the first histogram I get (102,121,160) instead of (0,32,96):
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/944069/image.png)
0 件のコメント
採用された回答
Steven Lord
2022 年 3 月 28 日
The histogram object has a FaceAlpha property, so that if you overlay two histogram objects you can see the one underneath. If you change that FaceAlpha property the color appears slightly different and may be closer to what you want.
x = randn(1, 100);
figure
h = histogram(x, 'FaceColor', 'r');
title("Histograph with FaceAlpha " + h.FaceAlpha)
figure
h = histogram(x, 'FaceColor', 'r', 'FaceAlpha', 1);
title("Histograph with FaceAlpha " + h.FaceAlpha)
その他の回答 (1 件)
Scott MacKenzie
2022 年 3 月 28 日
編集済み: Scott MacKenzie
2022 年 3 月 28 日
The histogram function uses a face alpha of 0.6 by default. That's why the colors appear a bit lighter than the values from your eye dropper app. If you set the face alpha to 1.0 (see below), then the displayed colors will agree with the eye dropper values.
colours = [0 32 96;
192 0 0;
71 207 255;
255 143 143;
] / 255;
for i=1:4
x = randn(1,100);
subplot(2,4, i)
values = histogram(x,'FaceColor', colours(i, :));
values.FaceAlpha = 1.0; % NOTE: default is 0.6
values.FaceColor * 255
end
3 件のコメント
Scott MacKenzie
2022 年 3 月 28 日
編集済み: Scott MacKenzie
2022 年 3 月 28 日
@z8080, hmm, right your are. I dug a bit deeper and discovered why there is a discrepancy between the set colors and the eye dropper colors. See my modified answer for the details.
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