Specifying encoding as a function
現在この質問をフォロー中です
- フォローしているコンテンツ フィードに更新が表示されます。
- コミュニケーション基本設定に応じて電子メールを受け取ることができます。
エラーが発生しました
ページに変更が加えられたため、アクションを完了できません。ページを再度読み込み、更新された状態を確認してください。
古いコメントを表示
Hello everyone,
I wrote a code for my genetic algorithm, but I can't specify it as a function, can you help please?
newM=birincifaz.*(1:size(birincifaz,1))';
newM(:,1)=[];
for k=1:size(newM,2)
r=unique(newM(:,k));
r=r(r~=0);
B(:,k)=r(randi(length(r),50,1));
end
yeni=ikincifaz.*(1:size(ikincifaz,1))';
yeni(:,1)=[];
for e=1:size(yeni,2)
m=unique(yeni(:,e));
m=m(m~=0);
H(:,e)=m(randi(length(m),50,1));
end
out = reshape(vertcat(B,H), 50, [])
採用された回答
Walter Roberson
2022 年 3 月 17 日
function out = TheFunctionName(birincifaz, ikincifaz)
However:
This will return an array whose first dimension is at least 50 -- so not a scalar. ga() requires that the function return a scalar, unless the 'UseVectorized' option is true. If UseVectorized is true, then the function needs to return a vector that is the same length as the number of rows in the input.
Also, if birincifaz and ikincifaz are both intended to be varied by ga() then you need to pack both of them into a single vector and extract them inside the function, such as
function out = TheFunctionName(x);
birincifaz = x(1:floor(end/2));
ikincifaz = x(floor(end/2)+1:end);
6 件のコメント
Yonca DOGU
2022 年 3 月 17 日
I'm facing an error, but I'll try again as you said thank you.
Walter Roberson
2022 年 3 月 17 日
B(:,k)=r(randi(length(r),50,1));
That use of randi() is a potential problem. Your objective function should always return the same results for the same inputs; othewise it becomes impossible to fairly compare the effects of changing the various parameters of the model.
Yonca DOGU
2022 年 3 月 18 日
I am getting error, how should i fix the code ?
Walter Roberson
2022 年 3 月 18 日
Post your current code.
Yonca DOGU
2022 年 3 月 18 日
Hi,
I tried the code like this but it didn't work, the part that I added later is written in bold;
function out = TheFunctionName(x);
birincifaz = x(1:floor(end/2));
ikincifaz = x(floor(end/2)+1:end);
end
newM=birincifaz.*(1:size(birincifaz,1))';
newM(:,1)=[];
yeni=ikincifaz.*(1:size(ikincifaz,1))';
yeni(:,1)=[];
for k=1:size(newM,2)
r=unique(newM(:,k));
r=r(r~=0);
B(:,k)=r(randi(length(r),168,1));
end
yeni=ikincifaz.*(1:size(ikincifaz,1))';
yeni(:,1)=[];
for e=1:size(yeni,2)
m=unique(yeni(:,e));
m=m(m~=0);
H(:,e)=m(randi(length(m),168,1));
end
out = reshape(vertcat(B,H), 168, [])
end
Attention: birincifaz and ikincifaz values are below.
birincifaz =
1 1 0 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
2 1 0 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
3 1 0 1 0 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
4 1 0 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
5 1 0 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
6 0 0 0 0 0 1 1 0 1 0 0 0 0 1 0 0 0 1 0 1 1 1 1 1 0 0 1 1 0 0 1 0 0 1 0 1 0 1 0 1 1 0 1 1 1 1 1 1 1 1 1 0 0 1 0 1 1 1 0 0 0 1 0 0 0 1 1 0 1
7 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
8 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
9 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
10 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
ikincifaz =
1 1 0 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
2 1 0 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
3 1 0 1 0 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
4 1 0 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
5 1 0 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
6 0 0 0 0 0 1 1 0 1 0 0 0 0 1 0 0 0 1 0 1 1 1 1 1 0 0 1 1 0 0 1 0 0 1 0 1 0 1 0 1 1 0 1 1 1 1 1 1 1 1 1 0 0 1 0 1 1 1 0 0 0 1 0 0 0 1 1 0 1
7 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
8 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
9 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
10 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
Thanks in advance
Walter Roberson
2022 年 3 月 18 日
As the 4th line of code you have an "end" statement. That tells MATLAB that you are finished entering the code of the function. Anything after that in the same MATLAB file would have to be one or more function definitions, each concluding with an "end" statement.
Exception: if there were already a "function" definition in process and
function out = TheFunctionName(x);
was in the middle of that other hypothetical function, then the code for that other hypothetical function could continue after the "end" statement for the new function.
You have two choices, depending what you are trying to do:
- You could move the "end" statement on line 4 to after all of other code, if that other code is intended to be part of the function; or
- You could move the four lines of function to after all of that other code, if the function is intended to be a helper function called from that other code.
その他の回答 (0 件)
カテゴリ
ヘルプ センター および File Exchange で Genetic Algorithm についてさらに検索
タグ
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!Web サイトの選択
Web サイトを選択すると、翻訳されたコンテンツにアクセスし、地域のイベントやサービスを確認できます。現在の位置情報に基づき、次のサイトの選択を推奨します:
また、以下のリストから Web サイトを選択することもできます。
最適なサイトパフォーマンスの取得方法
中国のサイト (中国語または英語) を選択することで、最適なサイトパフォーマンスが得られます。その他の国の MathWorks のサイトは、お客様の地域からのアクセスが最適化されていません。
南北アメリカ
- América Latina (Español)
- Canada (English)
- United States (English)
ヨーロッパ
- Belgium (English)
- Denmark (English)
- Deutschland (Deutsch)
- España (Español)
- Finland (English)
- France (Français)
- Ireland (English)
- Italia (Italiano)
- Luxembourg (English)
- Netherlands (English)
- Norway (English)
- Österreich (Deutsch)
- Portugal (English)
- Sweden (English)
- Switzerland
- United Kingdom (English)
