How to set upper and lower limit of random number

63 ビュー (過去 30 日間)
Stephen john
Stephen john 2022 年 3 月 16 日
コメント済み: Walter Roberson 2022 年 3 月 17 日
Hello everyone, I hope you are doing well. i have the following code. it generate a random number
I want to set the upper limit and lower limit for the values and generate a pattern.
for example i have value 350, then the lower limit will be 300 and upper limit will be 350, or any variable which define the upper and lower limit of the dataset., I have tried the following method but it does not work
levels=round(rand*498)+2;
Dataset=round(rand(1,1000)*(levels*1.1))+round(levels*0.5);
scatter(1:length(Dataset),Dataset)

回答 (2 件)

Voss
Voss 2022 年 3 月 16 日
lower_limit = 300; % to use your example values
upper_limit = 350;
% generate a uniformly distributed random *number* between lower_limit and
% upper_limit:
X = rand()*(upper_limit-lower_limit)+lower_limit
% generate a uniformly distributed pseudorandom *integer* between lower_limit
% and upper_limit:
X = randi(upper_limit-lower_limit+1)+lower_limit-1
  10 件のコメント
Stephen john
Stephen john 2022 年 3 月 17 日
@Walter Roberson not working getting error
Walter Roberson
Walter Roberson 2022 年 3 月 17 日
control = randi([2 1000], 1, 1000);
filtered = nan(size(control));
idx = find(control == 300);
if ~isempty(idx)
%talking about what happens when 300 is first found, is only meaningful
%if 300 was found at all
filtered(idx(1)) = randi([250 300], 1, 1); %250 to 300 the first time
idx = idx(2:end); %remaining locations
end
sometimes = rand(size(idx)) <= .3; %sometimes means a 30% chance, right?
filtered(idx(sometimes)) = randi([250 350], 1, nnz(sometimes));
idx = find(control == 500);
sometimes = rand(size(idx)) <= 0.64; %sometimes means a 64% chance, right?
filtered(idx(sometimes)) = randi([450 550], 1, nnz(sometimes));
%now verify
idx = find(~isnan(filtered))
idx = 1×3
301 707 877
control(idx)
ans = 1×3
500 300 500
filtered(idx)
ans = 1×3
545 294 507

サインインしてコメントする。


David Hill
David Hill 2022 年 3 月 16 日
dataSet=50*rand(1,1000)+300;
  8 件のコメント
Stephen john
Stephen john 2022 年 3 月 17 日
@David Hill the numbers are generated between 1-1000, then the upper and lower limit of the numbers depend on the span.
David Hill
David Hill 2022 年 3 月 17 日
r=998*rand(1,1000)+2;
span=100;
for k=1:1000
R(k,:)=span*rand(1,50)+r(k)-50;%each row is 50 samples within the +-50 of each element in r
end

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

製品


リリース

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by