my program is not working properly

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shiv gaur
shiv gaur 2022 年 3 月 11 日
コメント済み: Jan 2022 年 3 月 12 日
function kk2
close all; clear all;
% accuracy
%options = odeset('RelTol',1e-9,'AbsTol', 1e-16);
[t,y]=ode45(@f,[0 100],[0.1;0.1;0.1+1;0.1;0.1;0.1] );
plot(t,y(:,2),t,y(:,4),t,y(:,6))
function dy=f(t,y)
%x=y(1);y=y(3);z=y(5)
r=28;
b=8/3;
k=10;
dy=zeros(6,1)
dy= [y(2);k^2*y(1)-k^2*y(3)-k*y(1)*y(5)+k*r*y(5)-k*y(3);y(4);b*y(1)*y(5)-y(1)^2*y(3)-k*y(1)*y(3)+k*y(3)*y(5)-r*k*y(1)+k*r*y(3)+y(1)*y(5)-r*y(1)+y(3);y(6);-y(1)^2*y(5)+r*y(1)^2-y(1)*y(3)-k*y(1)*y(3)+k*y(3)^2-b*y(1)*y(3)+b^2*y(5)]
end
end
so sir we want to plot between t,x,t,y
and we want to plot t vs second element of dy t,fourth element t,vs sixth element
  1 件のコメント
Jan
Jan 2022 年 3 月 12 日
編集済み: Jan 2022 年 3 月 12 日
@shiv gaur: You have been asked repeatedly to use a proper code formatting. Please read and consider this: https://www.mathworks.com/matlabcentral/answers/help/rtc#rtc_summary . Thanks.

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回答 (1 件)

Sam Chak
Sam Chak 2022 年 3 月 11 日
編集済み: Sam Chak 2022 年 3 月 11 日
It appears that the system is highly unstable and all states blow up at around 0.35 sec except for . Please check the state equations again. Sometimes, the plus/minus signs can make a huge difference.
Edit: It has some similarities like the Lorenz system, because I recognized the magic values: 10, 8/3, 28.
clear all; clc
r = 28;
b = 8/3;
k = 10;
tspan = linspace(0, 0.3, 10001)';
fun = @(t, y) [y(2); ...
k^2*y(1) - k^2*y(3) - k*y(1)*y(5) + k*r*y(5) - k*y(3); ...
y(4); ...
b*y(1)*y(5) - y(1)^2*y(3) - k*y(1)*y(3) + k*y(3)*y(5) - r*k*y(1) + k*r*y(3) + y(1)*y(5) - r*y(1) + y(3); ...
y(6); ...
- y(1)^2*y(5) + r*y(1)^2 - y(1)*y(3) - k*y(1)*y(3) + k*y(3)^2 - b*y(1)*y(3) + b^2*y(5)];
[t, y] = ode45(fun, tspan, [0.1, 0.1, 1.1, 0.1, 0.1, 0.1]);
plot(t, y)
Once you have fixed the model, please ensure that all states can propagate at least until your desired final time, sec, and then you can choose what you want to plot.
  6 件のコメント
Jan
Jan 2022 年 3 月 12 日
@Sam Chak: Thanks for your effort. If a user ignores your help consequently, this is his problem.

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