Creating empty cell array with function

3 ビュー (過去 30 日間)
Carly Hudson
Carly Hudson 2022 年 2 月 28 日
コメント済み: AndresVar 2022 年 3 月 1 日
function link_set = build_links(link_vectors);
% Use the 'cell' 'and 'size' commands to create an empty cell array the
% same size as link_vectors, named 'link_set'
link_set = cell(1,size(link_vectors));
I am working on a project in MATLAB Grader and it has been a while since iv'e used MATLAB. I'm having trouble creating this array and I keep getting the "Not enough input arguments." error. Any help or guidamce would be greatly appreciated.
  3 件のコメント
Carly Hudson
Carly Hudson 2022 年 2 月 28 日
function link_set = build_links(link_vectors)
% Take a set of link vectors and augment each with a zero vector representing
% the base of the link
%
% Input:
%
% link_vectors: a 1xn cell array, each element of which is an mx1 vector
% from the base to end of a link, as seen in its *local* coordinate
% frame
%
% Output:
%
% link_set: a 1xn cell array, each element of which is a mx2 matrix whose
% first column is all zeros (representing the base of the link in its
% local frame) and whose second column is the link vector (end of the
% link) in its local frame
%%%%%%%%%%%%%%
% Use the 'cell' 'and 'size' commands to create an empty cell array the
% same size as link_vectors, named 'link_set'
%%%%%%%%%%%%%
% Loop over the vectors in link_vectors, constructing a matrix whose
% first column is all zeros and whose second column is the link vector,
% and saving this matrix in the corresponding column of link_set
end
this is the whole prompt. im just confused because link_vectors is something that already exists. so i dont know why i cant just call it in when i define link_set
AndresVar
AndresVar 2022 年 3 月 1 日
I see, well here is an example, for n=2, m=3. This function just creates a cell array the same size as the input, which is the first part of what your function should do.
anInput = {[1;2;3],[4;5;6]}; % variable to use as an input
size(anInput)
ans = 1×2
1 2
anOutput = theFunction(anInput); % function call returns an output
size(anOutput) % the function made an output with the same size as the input
ans = 1×2
1 2
function theOutput = theFunction(theInput) % function definition block
theOutput = cell(size(theInput));
%%% make a matrix
end
Btw to be clear in your actual example: link_vectors is an input, you call build_links, and it returns a copy of link_set.

サインインしてコメントする。

回答 (1 件)

KSSV
KSSV 2022 年 2 月 28 日
It seems you are straight away running the function. You need to provide the inputs to the function and then call the function.
link_vectors = rand(1,3) ; % define your input variables
% now call the function
link_set = build_links(link_vectors);
  1 件のコメント
Carly Hudson
Carly Hudson 2022 年 2 月 28 日
function link_set = build_links(link_vectors)
% Take a set of link vectors and augment each with a zero vector representing
% the base of the link
%
% Input:
%
% link_vectors: a 1xn cell array, each element of which is an mx1 vector
% from the base to end of a link, as seen in its *local* coordinate
% frame
%
% Output:
%
% link_set: a 1xn cell array, each element of which is a mx2 matrix whose
% first column is all zeros (representing the base of the link in its
% local frame) and whose second column is the link vector (end of the
% link) in its local frame
%%%%%%%%%%%%%%
% Use the 'cell' 'and 'size' commands to create an empty cell array the
% same size as link_vectors, named 'link_set'
%%%%%%%%%%%%%
% Loop over the vectors in link_vectors, constructing a matrix whose
% first column is all zeros and whose second column is the link vector,
% and saving this matrix in the corresponding column of link_set
end
this is the whole prompt. im just confused because link_vectors is something that already exists. so i dont know why i cant just call it in when i define link_set

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeFunction Creation についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by