how to write summation

pl write in this summation

Answer 1

[Walter Roberson]

offset = 1;    % Indices are 1-based in Matlab
S = 0;
for p = 0:i
   S = S + A(offset+p) * C(offset + i - p);
end

[shiv gaur]

sir ans must verify the result by taking any arbitary example

elabrate with example ans must be verify by taking any value

[Rik]

Also here: why do you ask Walter to provide values for A and C? Why don't you provide any?

[Walter Roberson]

A = [5 3 -1 2]

A = 1×4

5 3 -1 2

C = [8 -2 3 2]

C = 1×4

8 -2 3 2

i = 3

i = 3

offset = 1;    % Indices are 1-based in Matlab
S = 0;
for p = 0:i
   fprintf('p = %d, A(1+%d) = %d, C(1+%d-%d) = %d, product = %d\n', p, p, A(offset+p), i, p, C(offset+i-p), A(offset+p) * C(offset + i - p));
   fprintf('S before addition: %d\n', S);
   S = S + A(offset+p) * C(offset + i - p);
   fprintf('S after addition: %d\n', S);
end

p = 0, A(1+0) = 5, C(1+3-0) = 2, product = 10

S before addition: 0

S after addition: 10

p = 1, A(1+1) = 3, C(1+3-1) = 3, product = 9

S before addition: 10

S after addition: 19

p = 2, A(1+2) = -1, C(1+3-2) = -2, product = 2

S before addition: 19

S after addition: 21

p = 3, A(1+3) = 2, C(1+3-3) = 8, product = 16

S before addition: 21

S after addition: 37

S

S = 37

alternate_S = sum(A.*fliplr(C))

alternate_S = 37

[shiv gaur]

pl help to solve this problem

p=8/3;

r=25;

sigma=10;

npoints =5;

dt = 0.1;

a = zeros(npoints,1);

b = zeros(npoints,1);

c= zeros(npoints,1);

t = zeros(npoints,1);

a(1)=1;

b(1)=1;

c(1)=1;

suma=0;

sumb=0;

sumc=0;

sumS=0;

sumZ=0;

for i = 1:npoints-1

a(i+1)=((sigma)/(i+1))*(b(i)-a(i));

sumS=sumS+a(i)*c(i-npoints);

b(i+1)=(1/(i+1))*(r*a(i)-b(i)-sumS);

sumZ=sumZ+a(i)*b(i-npoints);

c(i+1)=(1/(i+1))*(sumZ-p*c(i));

suma=suma+a(i).*(t^i);

sumb=sumb+b(i).*(t^i);

sumc=sumc+c(i).*(t^i);

t(i+1) = t(i) + dt;

disp(sumS)

end;

[Rik]

This is an honest question: why don't you format your code? I'm serious. Why do you only use one of these three buttons?

And why do you insist on leaving out any interpunction from your text? Can't you see that makes it harder to read?

[Walter Roberson]

@shiv gaur

You are already asking for the solution to that power series in several questions. Concentrate on them, instead of asking here in comments on a completely different question.

Answer 2

[Jan]

S = 0;
for p = 1:i+1   % Indices are 1-based in Matlab
   S = S + A(p) + C(i - p);
end

[shiv gaur]

this is in multiplying in above figure your ans is why +

[shiv gaur]

why value not calculateable

[Torsten]

Maybe because you didn't specify A and C ?

[shiv gaur]

you take arbitary value for match

[Rik]

Changing + to * seems easy enough. What is your remaining issue? Why not accept this answer?

[shiv gaur]

elabrate with example ans must be verify by taking any value

[Rik]

Is your shift key broken? And the keys for the . , and ? symbols? That must be very difficult.

You didn't provide values for A, so apparently those don't matter. Why should Jan pick some numbers to show his code works? You could have done exactly like me: write the example below. Then you could actually show what your problem is. If you can't explain it in English, you should explain it in Matlab.

i=10;
A=rand(i+1,1);
C=rand(size(A));

S = 0;
for p = 1:i+1   % Indices are 1-based in Matlab
   S = S + A(p) + C(i - p);
end

Array indices must be positive integers or logical values.

And now we can see that Jan made a small mistake: he corrected the indexing of A, but forgot to fix the indexing of C. Walter has now posted an answer that fixes this.

Also, sending me emails will not do anything. You should format your code as code. It isn't hard. Press ctrl-E before you paste any code or use the bar that appears when you write . Using interpunction will also help. If you post code that doesn't run when you click the small run icon, then the problem is not that I haven't seen your research, the problem is that you didn't include all variable definitions. I did not close your question because I was unable to answer your question, I closed it because you seem to be unwilling to use the tools provided to you. If I insisted on answering your questions in a Dutch dialect, you would not be able to understand me and my answer would be useless to you. If you insist on not formatting your posts and not using any interpunction you make your responses almost useless as well.