addition loops in matlab
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assume i have a vector array:
a=[1 1 1 0 0 1 1 1]
how can i put loop such that if sum of any three successive elements is equal to 3, it prints 'ali'.
can it be done without loops?
3 件のコメント
Austin Decker
2022 年 2 月 12 日
Well, MATLAB is likely looping behind the scenes, but you could do this:
a = [1,1,1,0,0 1,1,1];
ind1 = 1:length(a) -2;
ind2 = ind1 + 2;
result = arrayfun(@(x,y) sum(a(x:y)),ind1,ind2);
qty = sum(result == 3);
disp(join(repmat("ali",qty,1),newline));
採用された回答
DGM
2022 年 2 月 12 日
編集済み: DGM
2022 年 2 月 12 日
This works easily enough. After R2016a, you can do the same with movsum().
a = [1 1 1 0 0 1 1 1];
if any(conv(a,[1 1 1],'valid')==3)
fprintf('ali\n')
end
4 件のコメント
DGM
2022 年 2 月 12 日
編集済み: DGM
2022 年 2 月 12 日
To omit nans:
a = [2 nan 1 1 0 0 nan 1 1 nan 1];
% using movsum
s = movsum(a,3,'omitnan');
any(s(2:end-1)==3)
% using conv
a(isnan(a)) = 0;
s = conv(a,[1 1 1],'valid');
any(s==3)
If the value range of a never extends beyond [0 1], then you could also simply treat any propagated NaNs as 0. This is simply because it wouldn't be possible to have a sum equal to 3 if the window size were also 3 and any element were anything other than 1.
a = [1 nan 1 1 0 0 nan 1 1 nan 1];
s = conv(a,[1 1 1],'valid') % this will pass NaN
any(s==3) % NaNs aren't equal to 3
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