Index must be a positive integer or logical

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John
John 2014 年 11 月 29 日
編集済み: Star Strider 2014 年 11 月 29 日
I'm am working on modeling the physical pendulum using 4th Runge-Kutta Method and and getting the error
"Attempted to access F_t_theta_v(1,-0.0885,0.8); index must
be a positive integer or logical. Error in PhyFinal (line 42)
k_v1 = h * F_t_theta_v( t(i), theta(i), v(i) );"
Not sure what is going on or why it's not working. Any explaination would be helpful!
%Define Variables
w0 = 1;
alpha = 0.2;
f = 0.52;
w = 0.666;
%define step size
h = 1;
%set t from 1 to 100 seconds
t = 1:h:100;
%Create placement to put values generated
theta = zeros ( 1 , length(t) );
v= zeros ( 1 , length(t) );
k_v1=zeros ( 1 , length(t) );
k_theta1=zeros ( 1 , length(t) );
%first initial conditions
theta(1)=-0.0885;
v(1)=0.8;
%Function.
F_t_theta_v = -w0^2 * sin(theta) - alpha * v + f * cos(w*t);
%Apply 4th RK
for i=1:(length(t)-1);
k_v1 = h * F_t_theta_v( t(i), theta(i), v(i) );
k_theta1 = h * v;
k_v2 = h * F_t_theta_v ( (t(i) + 0.5 * h), (theta(i) + 0.5 * k_theta1), (v + 0.5 * k_v1) );
k_theta2 = h * (v + k_v1);
k_v3 = h * F_t_theta_v ( (t(i) + 0.5 * h), ( theta (i) + 0.5 * k_theta2), (v + k_v1) );
k_theta3 = h * ( v + k_v2 );
k_v4 = h * F_t_theta_v ( ( t(i) + h ), ( theta(i) + k_theta3), ( v + k_v1));
k_theta4 = h * ( v + k_v3 );
dtheta = 1/6 * (k_theta1 + 2 * k_theta2 + 2 * k_theta3 + k_theta4);
dv = 1/6 * (k_v1 + 2 * k_v2 + 2 * k_v3 + k_v4);
theta(i + h) = theta(i) + dtheta;
v (i + h) = v(i) + dv;
end
%plot theta(t), might change to 'x' for consistency', and v(t)
figure(1);
plot ( v,theta)

採用された回答

Star Strider
Star Strider 2014 年 11 月 29 日
You need to define your Anonymous Function correctly:
%Function.
F_t_theta_v = @(t,theta,v) -w0^2 * sin(theta) - alpha * v + f * cos(w*t);
Change the variables in the argument list in ‘@(t,theta,v)’ if I got it wrong. (I used the name of your function as a clue!) Your function should work then. It should pick up the other variables it needs from your workspace, but they have to be defined before you define the function.
  2 件のコメント
John
John 2014 年 11 月 29 日
Okay that fixed one problem now it's saying "In an assignment A(I) = B, the number of elements in B and I must be the same.
Error in PhyFinal (line 58) theta(i + h) = theta(i) + dtheta;"
I thought have everything from 1 to length(t) should be right unless I'm missing something
Star Strider
Star Strider 2014 年 11 月 29 日
編集済み: Star Strider 2014 年 11 月 29 日
Good!
The new problem is with ‘dtheta’. You defined ‘v’ as a vector, and that propagates through to ‘dtheta’. You defined ‘theta(i+h)’ as a scalar, and you cannot assign a vector to a scalar.
If you want to define it as a vector,
theta(i + h, :) = theta(i) + dtheta;
should work.
If you don’t want to define it as a vector, you need to select one element of ‘dtheta’ instead of the entire vector.

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その他の回答 (1 件)

Azzi Abdelmalek
Azzi Abdelmalek 2014 年 11 月 29 日
Check your indices, if a is an array you can't write
a(1.8)
the index must be a positive integer or logical

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