Suppression failure on evalin command

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Ian
Ian 2014 年 11 月 28 日
編集済み: Jan 2017 年 8 月 12 日
I'm having a problem suppressing the evalin function when using it to change elements in a vector. The semi-colon isn't working. Is there a fix for this? Here's an example:
>> i=zeros(1,4);
>> evalin('base','i(1)=1');
i =
1 0 0 0
The semicolon doesn't suppress the output for some reason.

採用された回答

Mischa Kim
Mischa Kim 2014 年 11 月 28 日
編集済み: Mischa Kim 2014 年 11 月 28 日
Ian, put the semi-colon right after the i(1)=1 statement
evalin('base','i(1)=1;')

その他の回答 (2 件)

Jan
Jan 2017 年 8 月 11 日
編集済み: Jan 2017 年 8 月 12 日
It would be much more simple and efficient to omit the indirection over evalin:
i(1) = 1;
See the excellent explanations at tutorial:why-variables-should-not-be-named-dynamically-eval . You find a detailed analysis of the problems evalin causes here at: Answers: is-there-the-more-elegant-way-to-do-this#comment_476583

Ian
Ian 2014 年 11 月 28 日
So simple, yet so effective. Thanks!

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