Reshaping Structure in every iteration

Hi

I'm iterating a loop. And in each iteration, i make random numbers by using rand function. And in every new iteration, I increase the size of matrix (which is created by rand function).

What i'm doing is storing every random matrix in structure in every iteration. So, what i need is to reshape the structure in every iteration.(to be Rows*1).

My question is, how can i reshape the structure ?

I'll really appreciate it if some one can help me with that.

Thanks a lot.

[Jan]

What do you call "structure"? A STRUCT array? A struct containing arrays as fields? Please post the current code.

[mohammad rashidi]

R=5;
for i=1:10
    M(:,i).position=rand(R,1); 
    R=R+10;
end

This is not what i'm working on , but that's similar.

Thank you.

[Benjamin Thompson]

Your code seems to work. What specifically needs to be changed in the behavior?

>> R=5;
for i=1:10
    M(:,i).position=rand(R,1); 
    R=R+10;
end
>> M

M =

1×10 struct array with fields:

position

[mohammad rashidi]

As every random matrix has different rows, i want to gather all matrices in one matrix with the size of " rows*1 " at the end of each iteration.

[Jan]

It is still not clear. In each iteration only one matrix is created. What does "all matrices at the end of each iteration" mean then? What is "rows"? Do you want to append each new matrix to the existing one?

V = [];
for i = 1:10
    V = cat(1, V, rand(5 + 10 * (i - 1), 1));
    M(i).position = V ; 
end

[mohammad rashidi]

Exactly, i wanna append them. What i mean by " rows*1" is , i want to just have a final matrix with one column.

[Jan]

Okay, then I post this code as an answer.

Answer 1

[Jan]

V = [];
for i = 1:10
    V = cat(1, V, rand(5 + 10 * (i - 1), 1));
    M(i).position = V ; 
end

[mohammad rashidi]

Thank you Jan. It worked.

I really appreciate your help.