Cube Every Third Integer Using Nested Loop Structure
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Attempting to cube every third integer in an array using a for and if loop structure. Note, this is my first time creating a nested loop structure and need simple straightforward explanation as to why the code does not work.
for i = [1:16]
if (i/3==0)
i^3
else
i
end
end
回答 (1 件)
カテゴリ
ヘルプ センター および File Exchange で Loops and Conditional Statements についてさらに検索
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