How can I make randi() in a loop not choose the same number
3 ビュー (過去 30 日間)
古いコメントを表示
I have an array
x=zeros(1,36)
then i have inside a while loop:
while ....
y=randi(length(x));
z=randi(length(x));
How can i make it so that this doesnt choose the same number at all,
Note: the loop will end before it gets to 36 choices, so its not that it doesnt have a choice but to go over the same numbers again
0 件のコメント
採用された回答
Walter Roberson
2022 年 1 月 8 日
That would be a bit difficult. You would have to find a random number seed that you could set such that randi(36) happens to produce a permutation of the numbers 1 : 36. It could take a fair bit of work to find such a seed.
I would suggest that you take a completely different approach:
rand_y = randperm(length(x));
rand_z = randperm(length(x));
for K = 1 : length(x)
y = rand_y(K);
z = rand_z(K);
stuff
if some conditon;
break;
end
end
0 件のコメント
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Loops and Conditional Statements についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!