1-hour offset in time string conversion
古いコメントを表示
Hi there, I'm having trouble in converting string to datenum values. Somehow, there will be an offset of one hour when converting back to datestr. So, here is my example:
>> timestr = '1986-03-13T11:59:58.000Z';
>> test = datenum(timestr,'yyyy-mm-ddTHH:MM:SS.000Z')
test =
7.2544e+05
>> datestr(test,'yyyy-mm-ddTHH:MM:SS')
ans =
1986-03-13T12:59:58
To me, this seems pretty weird. I might be missing something very simple, though. I'd be glad if any of you could help me! Thanks
Dennis
1 件のコメント
Star Strider
2014 年 10 月 24 日
I suggest you report this as a bug, specifically because in R2014b I get an even weirder result from running your code:
1986-03-13T04:59:58
a -19 hour error!
採用された回答
その他の回答 (1 件)
カテゴリ
ヘルプ センター および File Exchange で Dates and Time についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!