Thanks for quoting my code!
The second column ‘Y Coordinate (mm)’ is identically zero. The griddata function will of course have a problem with that, since it wants vectors with variations, not contant values. So ‘Y Coordinate (mm)’ needs to be something other than a vector of zeros. I have no idea what the original problem is wth it, or if it is empirical (experimental) data or calculated data.
Nothing can be done with the matrix as it currently exists. It needs to have non-constant (and preferably unique) values in each variable. The matrix needs to be updated, or a new matrix substituted for it.
T1 = readtable('https://www.mathworks.com/matlabcentral/answers/uploaded_files/807619/URM_shear.xlsx', 'VariableNamingRule','preserve')
Stats = varfun(@(x)[min(x); max(x)], T1)
% First10Rows = T1(1:10,:)
% T1Sz = size(T1)
VarNames = T1.Properties.VariableNames;
N = 50; % Interpolation Matrix Size
xv = linspace(min(T1{:,1}), max(T1{:,1}), N); % Create Vector
yv = linspace(min(T1{:,2}), max(T1{:,2}), N); % Create Vector
[Xm,Ym] = ndgrid(xv,yv); % Create Interpolation Matrices
Zm = griddata(T1{:,1}, T1{:,2}, T1{:,3}, Xm, Ym); % Interpolate
figure
surfc(Xm, Ym, Zm)
grid on
shading interp
set(0, 'DefaultTextInterpreter', 'latex')
hcb = colorbar;
xlabel(hcb,'[{\it Pa}]');
hcb.Label.Interpreter = 'latex';
set(hcb,'TickLabelInterpreter','latex')
colormap(jet(50))
title ('EPX1','FontSize',13,'interpreter', 'latex')
set(0, 'DefaultTextInterpreter', 'latex')
hcb = colorbar;
hcb.TickLabelInterpreter='latex';
% ColorbarRulerProperties = hcb.Ruler
hcb.Ruler.TickLabelFormat = '%.2f';
set(hcb, 'Ticks', sort([hcb.Limits, hcb.Ticks]))
set(gca,'TickLabelInterpreter','latex')
% tix = hcb.Ticks;
% expstr = @(x) [x(:).*10.^ceil(-log10(abs(x(:)+(x==0)))) floor(log10(abs(x(:)+(x==0))))];
% tixexp = expstr(tix(:))
% tixexplbl = compose('%.2f \\times 10^{%2d}',[tixexp(:,1) fix(tixexp(:,2))])
% hcb.TickLabels = tixexplbl;
xlabel('{\it x} [{\it mm}]')
ylabel('{\it y} [{\it mm}]')
zlabel('{\it} Shear stress [{\it MPa}]')
.
