mean of matrix elements
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hey all. i have a 5760x1 matrix. i need to find the average of the first 10 elements, remove the 10 elements and replave with the averaged number, find the average of the next 10 elements, remove those 10 elements and replace with average and so on.... could anyone give me an insight as to how to do this? much appreciated john
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Andrew Reibold
2014 年 10 月 15 日
編集済み: Andrew Reibold
2014 年 10 月 15 日
myMatrix = rand(5760,1)
for jj = 1:576
moving_avg(jj,1) = mean(myMatrix(jj*10-9:jj*10));
end
Will make a matrix called 'moving_avg' where each point represents the average of each set of 10 points.
Is that what you wanted? It will be 1/10 the size.
1 件のコメント
Andrew Reibold
2014 年 10 月 15 日
Its very easy to replace every single point with the average too if thats what you need. (Same size, but every set of 10 numbers are all the same averaged number.)
Andrei Bobrov
2014 年 10 月 16 日
I want have 'vote' too!
out = accumarray(ceil((1:numel(x))'/10),x(:),[],@mean);
2 件のコメント
Sean de Wolski
2014 年 10 月 16 日
b=blkproc(rand(5760,1),[10,1],@mean)
I can't think of a solution shorter than my reshape one in terms of Code Golf?
john creighton
2014 年 10 月 16 日
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