Warning: Matrix is singular to working precision
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a=[1, 0, 0, 0, -0.25, 0; 0, 1, 0, -0.25, 0, -0.25; 1, 0, 0, 0, -0.25, 0; 0, -0.25 0, 1, 0, 0; -0.25, 0, -0.25, 0, 1, 0; 0,-0.25, 0, 0, 0, 1];
b=[6.25,4.45,6.8,5.5,3.87,6.45];
c=b/a;
Warning: Matrix is singular to working precision.
i dont know why?
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回答 (1 件)
Chunru
2021 年 11 月 14 日
編集済み: Chunru
2021 年 11 月 14 日
Make sure your matrix "a" is full rank (rank(a) should be 6 instead of 5).
a=[1, 0, 0, 0, -0.25, 0; 0, 1, 0, -0.25, 0, -0.25; 1, 0, 0, 0, -0.25, 0; 0, -0.25 0, 1, 0, 0; -0.25, 0, -0.25, 0, 1, 0; 0,-0.25, 0, 0, 0, 1]
rank(a)
b=[6.25,4.45,6.8,5.5,3.87,6.45]
c=b/a;
1 件のコメント
Walter Roberson
2021 年 11 月 14 日
The important point here is the fact that a has rank 5, so the matrix is singular.
Notice that your first and third row are the same. Any matrix which has identical rows will be singular .
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