Matlab Error after executing the code
2 ビュー (過去 30 日間)
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Dear sir/Madam
I have the following Matlab code.
clear all
clc
kc=[1 2 3 4 5 6 7 8 9 0];
k12=200;
k34=300;
new1=1:1:10;
for h1=1:length(new1);
for l1=1:length(new1);
K(h1,l1)=[k12 -k12 0 0;-k12 kc(h1,l1)+k12 -kc(h1,l1) 0;0 -kc(h1,l1) k34+kc(h1,l1) -k34;0 0 -k34 k34];
end
end
After executing it, an error is displayed as "Unable to perform assignment because the left and right sides have a different number of elements." Kindly provide any suggestions to avoid this error.
2 件のコメント
Sreedevi K
2021 年 11 月 4 日
You are trying to save a 4*4 matrix (RHS) into a single element (LHS) which is not allowed.
回答 (2 件)
Sreedevi K
2021 年 11 月 4 日
You have to save into a cell array or a 3D matrix. As shown below:
kc=[1 2 3 4 5 6 7 8 9 0];
k12=200;
k34=300;
new1=1:1:10;
count = 0 ;
for h1=1:length(new1)
for l1=1:length(new1)
count = count+1 ;
K{count}=[k12 -k12 0 0;-k12 kc(h1,l1)+k12 -kc(h1,l1) 0;0 -kc(h1,l1) k34+kc(h1,l1) -k34;0 0 -k34 k34];
end
end
0 件のコメント
VBBV
2021 年 11 月 30 日
clear all
clc
kc=[1 2 3 4 5 6 7 8 9 0];
k12=200;
k34=300;
new1=1:1:10;
for l1=1:length(new1)
K(:,:,:,:,l1)=[k12 -k12 0 0;-k12 kc(l1)+k12 -kc(l1) 0;0 -kc(l1) k34+kc(l1) -k34;0 0 -k34 k34];
end
K
clear K
TT = 1
for l1=1:length(new1)
K{TT}=[k12 -k12 0 0;-k12 kc(l1)+k12 -kc(l1) 0;0 -kc(l1) k34+kc(l1) -k34;0 0 -k34 k34];
TT = TT+1;
end
K
You need one for loop only to compute the matrix, Also, you were getting error because, when you access more elements from matrix than its actual dimension. You can do it using cell array as below
0 件のコメント
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