fmincon returns wrong length
3 ビュー (過去 30 日間)
古いコメントを表示
Hi! I have a large Simulink- Modell in which I want to optimize two PI- controllers. My variables are x_1... x_4 such as:
x = [Kp_1 Ti_1 Kp_2 Ti_2];
[x,f,eflag,output] = fmincon(@fun,x0,[],[],[],[],lb,ub,@mynlconst,opts);
In my nonlinear constrains I added 20 constrains, for example:
function [c,ceq] = mynlconst(x)
ceq = [];
set_param(char([SimName '/CF/Kp_1']), 'Gain', 'x(1)');
set_param(char([SimName '/CF/Ti_1']), 'Gain', 'x(2)');
% Same for x(3) and x(4)
opts = simset('DstWorkspace','current','SrcWorkspace','base');
sim(SimName,Tend,opts);
c(1) = max(yout(:,1)) - MaxPX;
c(2) = -min(yout(:,1)) - MinPX;
c(3) = max(yout(:,3)) - MaxTX;
c(4) = -min(yout(:,3)) - MinTX;
c(5) = max(yout(:,5)) - MaxHX;
c(6) = -min(yout(:,5)) - MinHX;
|
c(20)= ...;
yout is a matrix from Simulink with the size (130,variables). As constrains I've used the max, min of the vector.
My optimazion function fun (To keep it simple I just wrote the necessary parts):
function y = fun(x)
set_param(char([SimName '/CF/Kp_1']), 'Gain', 'x(1)');
set_param(char([SimName '/CF/Ti_1']), 'Gain', 'x(2)');
% Same for x(3) and x(4)
opts = simset('DstWorkspace','current','SrcWorkspace','base');
sim(SimName,Tend,opts);
y = e'*e; % e= error, imput of controller
Somehow I get a vector x length 130, my Sample lengh :( I just want a optimized variable x legnth 4.
Any suggestions?
Thank you!
0 件のコメント
採用された回答
Alan Weiss
2014 年 10 月 8 日
What is your x0 input to fmincon? The returned solution x has the same size as x0.
Alan Weiss
MATLAB mathematical toolbox documentation
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Nonlinear Control についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!