How do I make numbers shift left using function?

I have a function file that shifts the numbers to the left when called. But I dont know how to get it to loop so that it will keep shifting left.
function MyShiftLeft = MyShiftLeft(x)
y=[8 4 -2 5 4 0 -1]
temp=y(1); % save first value
% shift values left
for i=1:length(y)-1
y(i) = y(i+1);
end
% set last value to first
y(end)=temp;
y
When I use this code, it just keeps outputting the same one shifted matrix
n = input('Number of shifts to the left: ')
while n>0
MyShiftLeft
n-1
end

 採用された回答

Chetan Bhavsar
Chetan Bhavsar 2021 年 10 月 27 日
編集済み: Chetan Bhavsar 2021 年 10 月 27 日

0 投票

@Amy Joyce Valencia I think this will work for you
function Output = MyShiftLeft(y,x)
for j=1:x
temp=y(1);
% shift values left
for i=1:length(y)-1
y(i) = y(i+1);
end
% set last value to first
y(end)=temp;
end
Output=y;
end
Here is the output
>> MyShiftLeft([8 4 -2 5 4 0 -1],1)
ans =
4 -2 5 4 0 -1 8
>> MyShiftLeft([8 4 -2 5 4 0 -1],2)
ans =
-2 5 4 0 -1 8 4
>> MyShiftLeft([8 4 -2 5 4 0 -1],3)
ans =
5 4 0 -1 8 4 -2
>> MyShiftLeft([8 4 -2 5 4 0 -1],4)
ans =
4 0 -1 8 4 -2 5

2 件のコメント

Amy Joyce Valencia
Amy Joyce Valencia 2021 年 10 月 29 日
Is this the entire code? So I would just have to put the matrix in my regular code right? Not my function?
Amy Joyce Valencia
Amy Joyce Valencia 2021 年 10 月 29 日
This is what my function file has looked like. I think it's the regular code I'm having a hard time with.
x = input('Number of shifts to the left: ');
y= [8 4 -2 5 4 0 -1];
while x>0
MyShiftLeft
x = x-1;
end

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