Problem with FFT and IFFT back to time doman, not exactly the first signal.

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Filippos
Filippos 2014 年 10 月 3 日
回答済み: SK 2014 年 10 月 3 日
Hello all.
I am trying to reproduce the changes on a ~30 femtosecond laser pulse. I create and display this pulse in time just fine. Also, the fft of this pulse apperas fine on matlab (central frequency and width are very fine). But when I backtransform the transformed one using the ifft() function, the pulse is moved in time (posssibly due to phase change?? I don't know) and also the peak maxima are different.. What could be the cause of this? I am using ifft the wrong way?
The code I am using is this :
atto=1e-18;
c = 299792458;
femto=1e-15;
lamda0=800e-9;
f_0=c/lamda0;
omega0=2*pi*c/lamda0;
T=2*pi/omega0;
a=2*log(2)/((36.32*femto)^2);
Fs=3/atto; %samplying rate
t=-200*femto:1/Fs:200*femto;
Efield=exp(-a.*(t-T).^2).*exp(1j.*omega0.*(t-T));
nfft=2^nextpow2(length(Efield));
Efieldfft=fft(Efield,nfft);
f=(0:nfft-1)*Fs/nfft;
omega=2*pi*f;
figure(1)
plot(t,Efield)
xlabel('s [fs]')
ylabel('Amplitude')
figure(2)
plot(omega,abs(Efieldfft))
xlim([2e15 2.8e15])
xlabel('omega [rad]')
ylabel('Amplitude')
figure(3)
plot(f,abs(Efieldfft))
xlim([3.3e14 4.1e14])
xlabel('frequency [Hz]')
ylabel('Power')
test=ifft(Efieldfft,length(t));
figure(4)
plot(t,test)
xlabel('s[fs]')
ylabel('amplitude')
Test is the backtransformed function to time... Looking forward for your answers

採用された回答

SK
SK 2014 年 10 月 3 日
You have padded the original function with zeros upto the next power of 2. But when you take the inverse fft you only use the length of the original function. You need to put the full length of the fft back into the ifft function.

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