Why is my last line coming up as an empty sym?
1 回表示 (過去 30 日間)
古いコメントを表示
There's a couple steps to this problem. Expand and then simplify the equation. The last is to solve this equation: when x =2. But when I run it, it comes up empty
𝑦= (𝑥^3 +1)(𝑥^2 +2𝑥−5)(𝑥^2 −3)^2
clear
syms x
x==2
y = (x^3+1)*(x^2+2*x-5)*(x^2-3)^2 %deleted "eqn =' double = leads to error
expand(y) %switch out "eqn" with "y"
simplify(y) %same as above
solve(subs(y,x,2),y)
0 件のコメント
回答 (1 件)
Cris LaPierre
2021 年 10 月 22 日
I don't think you need to use solve in the final line. Substituting in 2 for x will return a value for y. There is nothing left to solve for.
syms x
y = (x^3+1)*(x^2+2*x-5)*(x^2-3)^2 %deleted "eqn =' double = leads to error
subs(y,x,2)
参考
カテゴリ
Help Center および File Exchange で Assumptions についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!