Creating new vector and using IF correct or loop?

1 回表示 (過去 30 日間)
Daniel
Daniel 2014 年 9 月 25 日
編集済み: Andrei Bobrov 2014 年 9 月 25 日
Hello,
I need some help with my matlab code.
I have two vectors of data: "position" and "time", The position vector has a maximum value of ~2 and a minimum value of ~-1. Booth vector are of 1x500000 points. My time vector looks like this: time=(0:length(position)-d)*dt %dt is the value between each point (2e-4), delta time
I want to be able to construct a new vector called "force".
This vector should be created by multiplication the position vector with a certain value. But I have different values for this multiplication. If the current value of the position is lower than 0.5, it should be multiplied with a certain value, x If it is between 0.5 and 1.5, it should be multiplied with a value, y. And so on...
I should then also be able to plot "time" vs "force".
I guess I should use some if and/or elseif commands. But how do I get it right?
Thank you.
  1 件のコメント
Image Analyst
Image Analyst 2014 年 9 月 25 日
Make it easy for people to help you by attaching a data file and a snippet of code to read it in to some variables.

サインインしてコメントする。

採用された回答

Adam
Adam 2014 年 9 月 25 日
Just put together a multiplication vector as e.g.
multVec = zeros( size( position ) );
multVec( position < 0.5 ) = m1;
multVec( 0.5 <= position & position < 1.5 ) = m2;
...
Then:
force = position .* multVec;
  1 件のコメント
Daniel
Daniel 2014 年 9 月 25 日
Thank you Adam, It works fine!

サインインしてコメントする。

その他の回答 (1 件)

Andrei Bobrov
Andrei Bobrov 2014 年 9 月 25 日
編集済み: Andrei Bobrov 2014 年 9 月 25 日
v = [-inf,.5,1.5,inf];
[~,ii] = histc(position,v);
m = [2 8 15]'; % example as m = [m1,m2,m3];
force = m(ii).*position;
  1 件のコメント
Daniel
Daniel 2014 年 9 月 25 日
Thank you, very helpful.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeMultidimensional Arrays についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by