how can access?

hi,

i have array , each row in this array contains data as follow: "1|Toy Story (1995)|01-Jan-1995||http://us.imdb.com/M/title-exact?Toy%20Story%20(1995)|0|0|0|1|1|1|0|0|0|0|0|0|0|0|0|0|0|0|0"

I want access to sequence of zero's and one's and ignore what before it in order to place these sequence into new vector.

who can help me?

thanks

Answer 1

[Fangjun Jiang]

If those 0s and 1s are always at the end and their repetition is consistent, you could do the following.

str='1|Toy Story (1995)|01-Jan-1995||http://us.imdb.com/M/title-exact?Toy%20Story%20(1995)|0|0|0|1|1|1|0|0|0|0|0|0|0|0|0|0|0|0|0'
NewStr=str(end-37:end);
NewStr=NewStr(2:2:end);
NewStr=str2num(NewStr')

Otherwise, use regexp()

Movie={'1|Toy Story (1995)|01-Jan-1995||http://us.imdb.com/M/title-exact?Toy%20Story%20(1995)|0|0|0|1|1|1|0|0|0|0|0|0|0|0|0|0|0|0|0';
       '2|GoldenEye (1995)|01-Jan-1995||http://us.imdb.com/M/title-exact?GoldenEye%20(1995)|0|1|1|0|0|0|0|0|0|0|0|0|0|0|0|0|1|0|0';
       '3|Four Rooms (1995)|01-Jan-1995||http://us.imdb.com/M/title-exact?Four%20Rooms%20(1995)|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|1|0|0'}
Found=regexp(Movie,'(\|[01]\|)+.+','match');
Data=cell(size(Found));
for k=1:size(Found,1)
    temp=Found{k};
    Data{k}=temp{1}(2:2:end)-'0';
end

[Walter Roberson]

Variant:

NewStr = str(end-37:end);

NewStr = NewStr(2:2:end) - '0';

with the str2num not required.

[Fangjun Jiang]

Thanks, Walter! I kept forgetting this trick.

[huda nawaf]

thanks, but what is 37, what is meaning

is 37 remining if deal with another row? such as :

02|GoldenEye(1995)|01-Jan-1995||http://us.imdb.com/M/title-exact?GoldenEye%20(1995)|0|1|1|0|0|0|0|0|0|0|0|0|0|0|0|0|1|0|03|FourRooms(1995)|01-Ja

thanks

[Fangjun Jiang]

In the example code in my answer, str contains one long string which is the information regarding one movie record. 37 means the last 37 characters which contain '|0|0|1...'. Run the code one line a time to see the result.

[Fangjun Jiang]

See update using regexp()

Answer 2

[Walter Roberson]

barpos = find(str == '|');
nums = str(barpos(5)+1:2:end) - '0';

Be careful, though, as the number of flags appears to be inconsistent. I count one more on the first example than in the second, if I assume that the '03|FourRooms...' is really the start of a new record that you have accidentally joined together with the GoldenEye row.