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how to create a matrix from a part of another matrix?

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Rachuan
Rachuan 2014 年 9 月 7 日
編集済み: Star Strider 2014 年 9 月 7 日
x= [1 54 61 23;71 4 79 33;12 34 65 89;]
I need to have y=[1 54;71 4] i meen, "y" must take the values X (1,1) (1,2) (2,1) (2,2)
how can i do it????

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Star Strider
Star Strider 2014 年 9 月 7 日
You essentially already did it. You simply need to use the correct index references:
x= [1 54 61 23;71 4 79 33;12 34 65 89];
y = x(1:2, 1:2);
  4 件のコメント
Rachuan
Rachuan 2014 年 9 月 7 日
It does, however if Ngl=1 y=[1;71] while the correct answer would be y=[1]
Ngl=3 y=[1 54 61;71 4 79] correct y=[1 54 61;71 4 79;12 34 65]
Star Strider
Star Strider 2014 年 9 月 7 日
編集済み: Star Strider 2014 年 9 月 7 日
That is not the result I get:
Ngl = 1
y = x(1:Ngl, 1:Ngl)
produces:
Ngl =
1
y =
1
and this code:
Ngl = 3
y = x(1:Ngl, 1:Ngl)
produces:
Ngl =
3
y =
1 54 61
71 4 79
12 34 65
If you want to add a limit to be certain ‘Ngl’ does not exceed the size of ‘x’, the code becomes:
Ngl = 3
Ngl = min([Ngl size(x)]);
y = x(1:Ngl, 1:Ngl)
With this check, ‘y’ will always be square, will start at the first row and column indices of ‘x’, and ‘y’ will not attempt to get values of ‘x’ that are beyond the index limits of ‘x’.

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