how to create 200 random matrices using loop..
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Abhishek sadasivan
2014 年 8 月 23 日
編集済み: Matz Johansson Bergström
2014 年 8 月 23 日
Hi..I want to create separate 200 random matrices of size 32*32 , and each to be multiplied with my input matrix..whether any looping is possible here ..please help ..
thank in advance
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Image Analyst
2014 年 8 月 23 日
編集済み: Image Analyst
2014 年 8 月 23 日
Try this:
tic;
inputMatrix = rand(32, 32); % Whatever you want...
for k = 1 : 200
thisRandomMatrix = rand(32,32); % Create new random matrix for this iteration.
storedMatrixes{k} = inputMatrix .* thisRandomMatrix ; % Multiply them
end
toc;
msgbox('Done with loop');
2 件のコメント
Image Analyst
2014 年 8 月 23 日
編集済み: Image Analyst
2014 年 8 月 23 日
They are separate. Each one is in its own cell. To sum up all the elements in a particular matrix you can extract it then sum it:
thisMatrix = storedMatrixes{10}; % Get matrix #10.
theSum = sum(thisMatrix(:)); % Sum of all elements of matrix #10.
You could also store them as planes/slices in a 3D matrix if you preallocate a 3D matrix for them.
その他の回答 (1 件)
Matz Johansson Bergström
2014 年 8 月 23 日
I have not tried it but something like this:
n=200;
tmp = rand(32,32,n);
and then to multiply each matrix
for i=1:n
in = in*tmp(:,:,i)
end
2 件のコメント
Matz Johansson Bergström
2014 年 8 月 23 日
編集済み: Matz Johansson Bergström
2014 年 8 月 23 日
I would argue that this is possible and very simple using a 3D matrix. The data is stored in another way, that's all and very efficient, because Matlab is made for matrices. For small matrices this does not really matter, but for larger ones it might make a difference.
My suggestion stacks the matrices into a 3d matrix and you can simply pick out the matrices like you would any other data structure.
Also, to sum all the matrices, you just have to write
sums = squeeze(sum(sum(tmp)))
This gives you the sum of all the elements in each matrix as a vector. Sums(i) contains the sum of matrix i.
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