Plot 3D Array Gain of 4x4 Planar Antenna Pattern + Weighting
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Hi folks
I created an uniform rectangula antenna array
f=3e9;
c=3e8;
lambda=c/f;
ura = phased.URA('Size',4, 'ElementSpacing',0.5*lambda);
As it is stated in the Help of the Phased Array Toolbox, it generates a 4x4 array in the yz-plane, which means that
% Azimuthal az
phi=0;
% Elevation el
theta=90;
1. Is this right?
Further, I would like to calculate the Array Gain A(psi), by using the dtft with
A(psi)= \sum_n a_n*z^n
z = e^(j*psi)
psi=(k_x,k_y,k_z)*d= wavefactor: (k*d*sin(theta)*cos(phi), k*d*sin(theta)*sin(phi), k*d*cos(phi))
k=2*pi/lambda = wavenumber
d=distance between array elements in (1/lambda)
Taking the values for theta and phi from above, I`ll get as a wavefactor only a value for the k_x direction, that is:
% psi= k*d = 2*pi/lambda*d = 2pi
Array Gain: I am trying to solve this problem with Z-Transformation but I dont get any reasonable results?
G = dtft(a_n,psi)
2. Is this right so far? How can I introduce the weights to the coefficients?
Moreover, I really would like to plot the Array Gain G in 3D polar plot.
3. How could I realize this?
I already found the Orfanidis`Toolbox but it does not help me. Looking forward to hearing from you guys.
Cheers, Bryana
回答 (1 件)
Honglei Chen
2014 年 8 月 14 日
If you mean directivity, you could do the following to generate the 3D plot
f=3e9;
c=3e8;
lambda=c/f;
ura = phased.URA('Size',4, 'ElementSpacing',0.5*lambda);
plotResponse(ura,f,c,'RespCut','3d','Unit','dbi','Format','polar')
7 件のコメント
Bryana
2014 年 8 月 14 日
Honglei Chen
2014 年 8 月 14 日
What do you mean by 3 dimensions? The syntax does plot a 3D radiation pattern.
Bryana
2014 年 8 月 14 日
Honglei Chen
2014 年 8 月 14 日
I'd say that is what you want, just points to a different direction and with a backlobe. You can adjust the element to remove the backlobe and also rotate the axes to get a similar plot
f=3e9;
c=3e8;
lambda=c/f;
ura = phased.URA('Size',4, 'ElementSpacing',0.5*lambda,...
'Element',phased.CosineAntennaElement);
plotResponse(ura,f,c,'RespCut','3d','Unit','dbi','Format','polar')
set(gca,'CameraUpVector',[1 0 0]);
Bryana
2014 年 8 月 15 日
Honglei Chen
2014 年 8 月 15 日
You can think that way, but the element pattern is 3D, also your example is a 3D polar plot. Everything plotted here is indeed in a 3D mesh grid. If you really want to see the axes, you can simply do
axis on
and you'll see axes. Is that your concern?
Bryana
2014 年 8 月 15 日
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