How to add the new delayed signal to the PLOT !
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Hey all, My code below is working, however by looking at the plot it seems it didn't draw the new delayed signals, It just plotted the second signal? Is it something to do with [xi,f]=ksdensity(Y+delay); I am not adding the delay?
x = sample1(:,1);
X = (x).';
y = sample2(:,1);
Y = (y).';
figure;
clf
fisrt = subplot(3,1,1);
[xi,f]=ksdensity(X);
plot(f,xi);
line(repmat(X,2,1),repmat([0;0.1*max(xi)],1,length(X)),'color','r' );
second = subplot(3,1,2);
[xi,f]=ksdensity(Y);
plot(f,xi);
line(repmat(Y,2,1),repmat([0;0.1*max(xi)],1,length(Y)),'color','r' );
[Rxx,lags] = xcorr(X,Y);
[Z,delay] = max(Rxx);
lags(delay);
if delay>0
hold(first,'on');
[xi,f]=ksdensity(Y+delay);
plot(first,f,xi);
else
hold(second,'on');
[xi,f]=ksdensity(X+delay);
plot(second,f,xi);
end
Cheers,
2 件のコメント
Fangjun Jiang
2011 年 8 月 29 日
See my comment in your previous question. You accepted the answer. What further work have you done?
http://www.mathworks.com/matlabcentral/answers/14446-plot-problem
Fangjun Jiang
2011 年 8 月 30 日
The same mistake was pointed out even earlier. So, instead of making the same mistake again and again, please make your own effort to read, understand and learn it.
http://www.mathworks.com/matlabcentral/answers/13110-signal-processing
採用された回答
その他の回答 (2 件)
Honglei Chen
2011 年 8 月 29 日
Hi Susan,
X+delay does not delay the signal, it merely adds an offset of delay's value to X. To delay a signal, you need to shift it in samples. One way to do it is to pad zeros in the front. For example, assume your delay is 1 second and your sampling frequency is also 1 second, then you need to insert 1 zero in front of signal, i.e., make
X_delay = [0 X];
HTH
9 件のコメント
Susan
2011 年 8 月 29 日
Honglei Chen
2011 年 8 月 29 日
If I understand correctly, Y is your signal so Y+delay simply adds an offset to your signal, not delays it.
Susan
2011 年 8 月 29 日
Fangjun Jiang
2011 年 8 月 29 日
I can't believe it! If x and y are two similar signals, y is 2 seconds lagging behind x, to make x and y match, you need to SHIFT y signal 2 seconds forward (move left in time axle), or shift x signal 2 seconds backward (move right in time axle). You can't add 2 to the numerical value of x or y. I've explained this three times! You just couldn't get it, could you?!
Susan
2011 年 8 月 29 日
Honglei Chen
2011 年 8 月 29 日
It is difficult to do it without format so I'll open a new answer here to illustrate what I mean.
Susan
2011 年 8 月 29 日
Fangjun Jiang
2011 年 8 月 29 日
I am amazed by the way you learn. The way for "applying it" has been given in this answer and many other answers. If you spend more time reading it and understanding it, instead of asking the same question repeatedly, your problem may already be solved.
lamawal Jonathan
2014 年 11 月 30 日
Hello All! i'm on a similar problem (zero pad a signal), the slight difference is that my signal is a vector of single row and 2400 columns. each time i zero pad, it gives me the following error;
"Error using vertical
Dimensions of matrices being concatenated are not consistent."
i even tried running your code several times but it repeats same error on line 5 (y = [ zeros(N,1) ; x ];) of your code. pls, help i'm very new to matlab and it's very important for me.
Honglei Chen
2011 年 8 月 29 日
Hi Susan,
Let's say I have two signals x and y. To make it simple, let's say
x = [1 1 1 1 1 ]
so if y is the same as x but delayed by 2 samples, you would see
y = [0 0 1 1 1]
for the first 5 samples. However, if you do
x+2
you will get
[3 3 3 3 3]
which is not the delayed version.
HTH
3 件のコメント
Susan
2011 年 8 月 29 日
lamawal Jonathan
2014 年 11 月 30 日
Hello All! i'm on a similar problem (zero pad a signal), the slight difference is that my signal is a vector of single row and 2400 columns. each time i zero pad, it gives me the following error;
"Error using vertical
Dimensions of matrices being concatenated are not consistent."
i even tried running your code several times but it repeats same error on line 5 (y = [ zeros(N,1) ; x ];) of your code. pls, help i'm very new to matlab and it's very important for me.
Honglei Chen
2014 年 12 月 1 日
Your signal is a row vector, so it should be y=[zeros(1,N) x].
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