Extract element from column vector with condition
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I have column vector
P=[ 0; 212; 111; 190; 0; 223; 123; 200; 189; 219; 0; 190; 175; 202; 167; 181
....and so on]
I want to extract the 2nd and 3rd elements from the left 0 element IF LENGTH BETWEEN TWO 0 (the left 0 and right 0) is GREATER THAN 3. Save 2nd position elements in P2 column vector and 3rd position elements in P3 column vector. The result should be
After extraction, the remaining elements should be placed into P1 such as
P1 = [ 0; 212; 111; 190; 0; 223; 189; 219; 0; 190; 167; 181 ....and so on]
P2 = [123; 175]
P3 = [200; 202]
7 件のコメント
Azzi Abdelmalek
2014 年 8 月 8 日
There is no P2 in your result, what is P0? Can you remove the symbols *?
Sagar Dhage
2014 年 8 月 8 日
Azzi Abdelmalek
2014 年 8 月 8 日
How did you get P1?
Sagar Dhage
2014 年 8 月 8 日
Azzi Abdelmalek
2014 年 8 月 8 日
This is not clear, what about 212 and 111 the second and the third element of P?
Sagar Dhage
2014 年 8 月 8 日
Image Analyst
2014 年 8 月 8 日
編集済み: Image Analyst
2014 年 8 月 8 日
It might be clearer if you said "is 4 or more" rather than is "greater than 3". So the left run has 121, 111, 190 and that's 3, but not more than 3 (not 4 or greater) so those are left alone and get transferred to P1.
It's fairly easy if you have the Image Processing Toolbox. Do you?
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その他の回答 (2 件)
Azzi Abdelmalek
2014 年 8 月 8 日
編集済み: Azzi Abdelmalek
2014 年 8 月 8 日
Edit
P=[ 0; 212; 111; 190; 0; 223; 123; 200; 189; 219; 0; 190; 175; 202; 167; 181 ]
ii=strfind(P'~=0,[0 1])
idx=ii([diff([ii numel(P)])]>4)
P1=P'
jj=[idx+2 idx+3]
P1(jj)=[]
P2=P(idx+2)'
P3=P(idx+3)'
Image Analyst
2014 年 8 月 8 日
Method using the Image Processing Toolbox:
P=[ 0; 212; 111; 190; 0; 223; 123; 200; 189; 219; 0; 190; 175; 202; 167; 181]
P2 = [];
P3 = [];
measurements = regionprops(P~=0, P, 'PixelValues', 'Area')
for k = 1 : length(measurements)
% Show length of this stretch in the command window:
fprintf('Area of stretch #%d = %d\n', k, measurements(k).Area);
% Tack onto P2 and P3 if the length >= 4.
if measurements(k).Area >= 4
P2 = [P2, measurements(k).PixelValues(2)];
P3 = [P3, measurements(k).PixelValues(3)];
end
end
% Show in command window:
P2
P3
3 件のコメント
Sagar Dhage
2014 年 8 月 12 日
編集済み: Sagar Dhage
2014 年 8 月 12 日
Image Analyst
2014 年 8 月 12 日
I'm leaving on a week long trip in an hour. It looks like you've accepted an answer so then just go with that.
Sagar Dhage
2014 年 8 月 22 日
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