How to generate and calculate with empty values of matrix-elements
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PROBLEM:
I want to use logical functions to perform calculations between
matrices and don't know how to generate an empty value NaN.
EXAMPLE:
I use the two matrices below and if the conditions are not satisfied,
the output should be empty:
clear all;
close all;
m=rand(10,5);
n=rand(10,5);
T = zeros(size(m)); % Make another array to fill up...
for i = 1:numel(m)
if m(i)>.5 && n(i)>.5
T(i) = m(i+1)+n(i+1);
else
T(i) = 'NaN';
end
end
However, I obtain the following error:
??? In an assignment A(I) = B, the number of elements in B and
I must be the same.
I hope someone know the correction of this mistake
Thank you in advance
Emerson
1 件のコメント
Oleg Komarov
2011 年 8 月 28 日
Please format the code as indicated here: http://www.mathworks.com/matlabcentral/answers/13205-tutorial-how-to-format-your-question-with-markup
採用された回答
その他の回答 (1 件)
Oleg Komarov
2011 年 8 月 28 日
You can write directly:
NaN
instead of
'NaN'
but my suggestion would be to preallocate NaNs directly and delete the else part:
T = NaN(size(m))
The other problem is that you are assigning to T(i) the next values in m and n, but if i = 50 then the index will exceed the matrix dimensions.
So, what do you want to accomplish here? (you can also avoid the loop)
EDIT replaced & with |:
m = rand(10,5);
n = rand(10,5);
T = [m(2:end,:) + n(2:end,:); NaN(1,size(m,2))];
T(m(1:end-1,:) <= .5 | n(1:end-1,:) <= .5) = NaN;
9 件のコメント
Emerson De Souza
2011 年 8 月 28 日
Oleg Komarov
2011 年 8 月 28 日
For the first situation:
Tij = f(Mij,Nij) no problem but what is the logical function? Almost sure that with logical indexing the loop can also be avoided.
For the second situation:
Tij = f(M(i+x)j,N(i+x)j) again what is the logical function and the values of x?
Cannot help more than that w/o additional details.
Emerson De Souza
2011 年 8 月 28 日
Oleg Komarov
2011 年 8 月 28 日
You have to decide what to do with the last row of T, do you want it to be NaN, because obviously it cannot be:
T_last,j = m_(last+1),j + n_(last+1),j
unless T is k by z and m,n are k+1 by z.
Emerson De Souza
2011 年 8 月 28 日
Emerson De Souza
2011 年 8 月 30 日
Oleg Komarov
2011 年 8 月 30 日
Replace the & with an |.
Emerson De Souza
2011 年 8 月 30 日
Oleg Komarov
2011 年 8 月 30 日
You have to be careful when checking m and n, if their first element are both bigger than .5 then the first element of T is the sum of the SECOND elements of m and n.
After correcting for the | I do get consistent results. Try to replace in my example:
m = rand(3);
n = rand(3);
You'll be able to visualize and compare more easily.
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