Conversion to double from sym is not possible

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Yunho Choi
Yunho Choi 2011 年 8 月 27 日
To use command 'solve',syms * * *.
After solve equation, i want plot. but it dosen't work
Conversion to double from sym is not possible
how to change dobule to sym...
or how to use solve without syms * * * only using double.
this is my code and answer. help me guys
syms x R2 R1;
[R2,x]=solve('a*(((1-R2)/(1-R1))+1)*x^2+((b+c)*(1-R2))*x+a*(((1-R2)/(1-R1))*R1+R2)=0','(b*((1-R2)/(1-R1))*R1-c*R2)*x^2+b*((1-R2)/(1-R1))-c=0','R2,x');

採用された回答

Walter Roberson
Walter Roberson 2011 年 8 月 27 日
Are a, b, and c specific numeric values that are already defined in your workspace? When you use quoted strings for solve() the way you do, solve() does not know to fetch the values of the variables from the workspace and will treat the values as being symbolic.
If a, b, and c do have specific values, you could change your code to
[R2, x] = solve(a*(((1-R2)/(1-R1))+1)*x^2+((b+c)*(1-R2))*x+a*(((1-R2)/(1-R1))*R1+R2, (b*((1-R2)/(1-R1))*R1-c*R2)*x^2+b*((1-R2)/(1-R1))-c, R2, x);
Then the results returned would be symbolic only in terms of R1.
Because, though, they would contain a symbol, you would not be able to plot them directly. You could use subs() as Paulo suggests, but it might be easier to instead use
fR2 = matlabFunction(R2);
fx = matlabFunction(x);
and then fR2 and fx would be function handles to functions of a single input, suitable for something like
r1vals = 0:.05:10;
plot(r1vals, fR2(r1vals), 'r', r1vals, fx(r1vals), 'g');

その他の回答 (1 件)

Paulo Silva
Paulo Silva 2011 年 8 月 27 日
Your expressions R2 and x got several symbolic variables and because of that you can't convert it to double (by using double(expression)), you must replace those symbolic variables by double values and after it use double(R2) and double(x)
doc subs %see the documentation of the subs function

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