How to loading a vector with values from a logical index
古いコメントを表示
I have a vector, Vin, of length m. I also have a logical vector, Idx, to select indices to work on (subset size n < m). I can operate on Vin(Idx) and get Vdata of length n. This is all good. But now I want to generate a new Vout vector that is filled with the values from Vdata at the appropriate index. This can be accomplished by the following code snippet.
Vout=zeros(length(Vin));
k = 1;
for j = 1:length(Vin)
if Idx(j)
Vout(j) = Vdata(k);
k = k + 1;
end
end
This seems verbose ? Is there a more efficient or correct way of doing this? i want the output vector to be of length m, not n
回答 (1 件)
Sara
2014 年 7 月 16 日
Vout = Vin(Idx)
4 件のコメント
Timothy Carnahan
2014 年 7 月 16 日
Sara
2014 年 7 月 16 日
Vout = zeros(length(Vin),1);
Vout(Idx) = Vin(Idx);
Timothy Carnahan
2014 年 7 月 16 日
Sara
2014 年 7 月 16 日
You may want to do zeros(length(Vin),1), otherwise you get a square matrix instead of a 1d array for Vout
カテゴリ
ヘルプ センター および File Exchange で Creating and Concatenating Matrices についてさらに検索
製品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!